A rectangle does not have a diameter, as such, but the diagonal is similar enough. If the sides of a rectangle are x cm and y cm then, using Pythagoras's theorem, the diagonal is sqrt(x2 + y2) cm.
t2 ÷ (2( π + 4) π = pi
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
It is called a diagonal and goes from any vertex to the next-but-one vertex.
A rectangle is an elongated square. It doesn't have a diameter; only circles have diameters.
Do you mean perimeter? If so....2 x length + 2 x width.
A rectangle does not have a diameter, as such, but the diagonal is similar enough. If the sides of a rectangle are x cm and y cm then, using Pythagoras's theorem, the diagonal is sqrt(x2 + y2) cm.
It can have any value up to 392 square cm.
add the perimeter of the rectangle, minus the side that'c covered by the semi circle. then, find the circumference of the semi circle [diameter x pi, divided by 2] and addd them together
No. The diagonal of the rectangle is a little over 32.2, and nothing that long can fit into a circle with a diameter of 27.
Divide the surface area by the circumference of the circle, which is a product of the diameter x Pi. Essentially, an unrolled cylinder is a rectangle.
Yes and the diameter of the circle will be the diagonal of the rectangle.
Area of circle = pi*212 = 1385.44236 square cm Area of rectangle = 1385.44236 square cm Lenght of rectangle = 1385.44236/18 = 76.96902 cm Perimeter of rectangle = 2(76.96902)+2(18) = 189.93804 cm
A rectangle does not have a diameter but it has diagonals. So using Pythagoras' theorem each diagonal is about 351.141mm in length rounded to 3 decimal places.
Question: In figure, what is the ratio of the areas of a circle and a rectangle if the diagonal of rectangle is equal to diameter of circle.
t2 ÷ (2( π + 4) π = pi