to find the y-intercept you plug in your x and y values in to the equation of y=mx+b. b is the y intercept and m is the slope. To find the x-intercept, set y = 0, and find value of x that satisfies the equation. If it is a line in the form y=mx+b, then the x-intercept will be at x= -b/m
y = {slope}x + {y intercept}
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
The y-intercept is whatever number (with no variable) is added onto the end of the equation y=mx+b. In this case b is the y-intercept. In y=15x the y-intercept is 0 because there is no number without a variable on the end.
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To find the x-intercept you need to set y=0 in your equation. To find the y-intercept you need to set x=0 in your equation.
If the x intercept is a and the y intercept is b, then the equation of the line is bx + ay = ab
-- In the equation of the graph, set x=0. -- Solve the equation for 'y'. -- The value you get for 'y' when x=0 is the y-intercept.
to find the y-intercept you plug in your x and y values in to the equation of y=mx+b. b is the y intercept and m is the slope. To find the x-intercept, set y = 0, and find value of x that satisfies the equation. If it is a line in the form y=mx+b, then the x-intercept will be at x= -b/m
At the x-intercept on the graph of the equation, y=0. Take the equation, set 'y' equal to zero, and solve the equation for 'x'. The number you get is the x-intercept.
y = {slope}x + {y intercept}
y=-4
First write it in the "slope-intercept" form : y = mx + c Then the y-intercept is (0, c)
Substitute zero for x to find the y-intercept, and substitute zero for y to find the x-intercept.
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A normal slope-intercept form equation would read: y = mx + b The slope of an equation is also known as 'm'. The y-intercept would count as 'b'. So in a random equation such as: y= 5x + 6 '5' would be the slope and '6' would be the y-intercept.
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