All triangles have an altitude. In fact they all have three of them. Whether or not they have an altitude, the important thing when trying to determine the length of the hypotenuse is what information you have on the lengths of the sides.
Altitudes, medians can help determine the lengths of sides, as can angles. You need a minimum of 3 pieces of information. There is only one in the question: the fact that the triangle has a right angle.
The median to the hypotenuse of a right triangle that is 12 inches in length is 6 inches.
the length of the hypotenuse is 10.63
The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 is: 10
A hypotenuse is the longest side of a right angled triangle. The length of a hypotenuse can be found using the Pythagorean Theorem. This states that in a right angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides. This means that to find the length of the hypotenuse, you need to know the lengths of the other two sides.
Using Pythagoras' theorem for a right angle triangle its hypotenuse length is 78 in.
The altitude of a right triangle if the base is 96 and the hypotenuse is 240 is: 229.87
What a neat little problem ! I'll remember this one, and I'll use it. The altitude to the hypotenuse is 12.0 millimeters long.
The median to the hypotenuse of a right triangle that is 12 inches in length is 6 inches.
The length of the hypotenuse of a right triangle with legs of lengths 5 and 12 units is: 13The length of a hypotenuse of a right triangle with legs with lengths of 5 and 12 is: 13
Sqrt x2+y2
The length of a hypotenuse with the right triangle sides of 15 and 36 is: 39
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2
the length of the hypotenuse is 10.63
It is: c2-b2 = a2 whereas c is the hypotenuse, b is the base and a is the altitude
By using Pythagoras' theorem: hypotenuse^2 minus base^2 = altitude^2
A right triangle has a hypotenuse of length 10 and a leg of length 7 has an area of: 24.99 units2