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How do you find the perimeter of a rectangle whose diagonal is 17.55 cm with an area of 109.35 square cm in step by step stages?
Wiki User
∙ 9y ago
Another Answer:-
Let the dimensions of the rectangle be x and y which are squared and square the diagonal and the area:-
Using Pythagoras: x+y = 308.0025 => y = 308.0025-x
Area: xy = 11957.4225 => x(308.0025 -x) = 11957.4225
So it follows: 308.0025x -xsquared -11957.4225 = 0
Solving the quadratic equation: x = 262.44 or x = 45.5625
Square root of both number: x = 16.2 and x = 6.75
By substitution: x = 16.2 and y = 6.75
Perimeter: 2(16.2+6.75) = 45.9 cm
Check: 16.2*6.75 = 109.35 square cm
Wiki User
∙ 9y ago
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What is the hypotenuse and perimeter of a right angle triangle when one side is greater than the other side by 45.5 cm and having an area of 2535 square cm showing all work in step by step stages?
As an intermediate step, calculate the two sides adjacent to the right angle first. Once you have that, you can easily calculate the hypotenuse and the perimeter.You'll have to write an equation to calculate the sides. Use the equation for the area of a triangle. I suggest you set:"x" for one side"x + 45.5" for the other sideAnother Answer:-1 Let the sides be x+45.5 and x2 0.5*(x+45.5)*x = 2535 which transposes to: x2+45.5x-5070 = 03 Solving the above quadratic equation gives x a positive value of 524 So sides are 52+45.5 = 97.5 cm and 52 cm5 Using Pythagoras: 97.52+522 = 12,210.252 and its square root is 110.56 Hypotenuse = 110.5 cm7 Perimeter = 97.5+52+110.5 = 260 cm
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