As an intermediate step, calculate the two sides adjacent to the right angle first. Once you have that, you can easily calculate the hypotenuse and the perimeter.
You'll have to write an equation to calculate the sides. Use the equation for the area of a triangle. I suggest you set:
"x" for one side
"x + 45.5" for the other side
Another Answer:-
1 Let the sides be x+45.5 and x
2 0.5*(x+45.5)*x = 2535 which transposes to: x2+45.5x-5070 = 0
3 Solving the above quadratic equation gives x a positive value of 52
4 So sides are 52+45.5 = 97.5 cm and 52 cm
5 Using Pythagoras: 97.52+522 = 12,210.252 and its square root is 110.5
6 Hypotenuse = 110.5 cm
7 Perimeter = 97.5+52+110.5 = 260 cm
Area: 0.5*(29.75+19.25)*height = 171.5 square cm Height: (171.5*2)/(29.75+19.25) = 7 cm The isosceles trapezoid will have right angle triangles at each side with a base of (29.75-19.25)/2 = 5.25 cm so use Pythagoras to find its hypotenuse:- Pythagoras: 7 squared+5.25 squared = 76.5625 and square root is 8.75 Perimeter: 8.75+8.75+29.75+19.25 = 66.5 cm
To create three different drawings showing a number of circles and triangles in which the ratio is 2:3 you can: Start with an equilateral triangle, draw a circle inside it, draw an equilateral triangle inside the circle, draw a circle in the triangle and then draw an equilateral tiangle in the smallest circle. Or, you could draw 3 triangles and 2 circles in a line. Or, you could draw 3 triangles on a line with 2 circles between them.
ASA is not a triangle, it is a method of proving that two triangles are congruent. ASA refers to showing that if two angles and a side (Angle-Side-Angle) of one triangle are the same measures as the corresponding angles and side of another triangle, then the two triangles are congruent. Since the three angles sum to 180 degrees, if two of them in one triangle are equal to the corresponding angles in the second triangle, then the third set of angles must also be equal. Consequently, ASA is equivalent to AAS and SAA. That is NOT The case with two sides and an angle, where it must be the included angle that is equal.
Area: 0.5*9.96*height = 33.0672 sq cmHeight: (33.0672*2)/9.96 = 6.64 cmAn isosceles triangle is in effect two right angle triangles joined together at its line of symmetry and in this case have bases of 9.96/2 = 4.98So using Pythagoras: 6.64 squared+4.98 squared = 68.89Square root of 68.89 = 8.3 which is its hypotenusePerimeter therefore is: 8.3+8.3+9.96 = 26.56 cmBase angles: tangent^-1(6.64/4.98) = 53 degrees to nearest degree
First find its height and then use Pythagoras to find its equal sides:- Area: 0.5*(sum of parallel sides)*height = 183.96 Height: (2*183.96)/(10.33+20.33) = 12 cm Each side will have a right angle with bases of 5 cm Using Pythagoras each equal side lengths are 13 cm Perimeter therefore is: 13+13+10.33+20.33 = 56.66 cm
Let its sides be 3x and 4x If: 0.5*3x*4x = 18.375 Then: 12x^2 = 36.75 => x^2 = 3.0625 => x = 1.75 So sides are: 5.25 cm and 7 cm Using Pythagoras its hypotenuse is: 8.75 cm Perimeter: 5.25+7+8.75 = 21 cm
1 Let the sides be x+14 and x 2 So: 0.5*(x+14)*x = 240 which transposes to x2+14x-480 3 Solving the above quadratic equation gives x a positive value of 16 4 Therefore the sides are 30 and 16 5 Using Pythagoras: 302+162 = 1156 and its square root is 34 6 Hypotenuse = 34 cm 7 Perimeter = 34+30+16 = 80 cm
1 Let the sides be: x+4.75 and x2 If: 0.5*(x+4.75)*x = 135.3753 Then: x2+4.75x-270.75 = 04 Using the quadratic equation formula: x has a positive value of 14.255 Therefore: sides are 14.25+4.75 = 19 cm and 14.25 cm6 Using Pythagoras: 192+14.252 = 564.0625 and its square root is 23.757 Hypotenuse: 23.75 cm8 Perimeter: 23.75+19+14.25 = 57 cm9 Check: 0.5*19*14.25 = 135.375 square cm
1 Let its height be x+1.45 and its base be x2 So: 0.5*(x+1.45)*x = 12.615 multiply both side by 23 Therefore: x2+1.45x-25.23 = )4 Using quadratic equation formula gives x a positive value of 4.355 It follows: height = 5.8 and base = 4.356 Using Pythagoras: hypotenuse = 7.257 Perimeter: 5.8+4.35+7.25 =17.4 cm
1 Let the sides be (x+26.25 cm) and x cm2 If: 0.5*(x+26.25)*x = 421.875 => x2+26.25x = 421.875*23 Then: x2+26.25x-843.75 = 04 Solving the above quadratic equation gives x a positive value of 18.755 Therefore sides are:18.75+26.25 = 45 cm and 18.75 cm6 Using Pythagoras: 452+18.752 = 2376.5625 and its square root is 48.757 Hypotenuse: 48.75 cm8 Perimeter: 48.75+45+18.75 = 112.5 cm9 Check: 0.5*45*18.75 = 421.875 square cm
what is the difination of showing the greater class
1 Let the sides be: x+3.5 and x 2 Using Pythagoras: (x+3.5)(x+3.5)+x2 = 17.52 3 So it follows: 2x2+7x-294 = 0 4 Solving the quadratic equation: x has a positive value of 10.5 5 Perimeter: (10.5+3.5)+10.5+17.5 = 42 cm 6 Area: 0.5*14*10.5 = 73.5 square cm
1 Let the sides be 5x and 12x 2 So: 0.5*5x*12x = 91.875 and then 60x2 = 183.75 3 Divide both sides by 60 and then square root both sides 4 Therefore x = 1.75 and sides are 5*1.75 = 8.75 and 12*1.75 = 21 5 Using Pythagoras: 8.752+212 = 517.5625 and its square root is 22.75 6 Hypotenuse = 22.75 cm 7 Perimeter = 8.75+21+22.75 = 52.5 cm
according to the formulae : area of triangle = (1/2) x base of triangle x height 54=(1/2)xBxH B x H = 108 now we have to factorize it.. factors can be.. (12,9),(27,4)(18,6)(36,3) now its given perimeter=36 we have to check two condition for the tringle to be right angle triangle sum of two sides > third side sum of the square of the two sides of triangle(shorter sides)= square of the third side. only one factor (12,9) satisfies both the conditions.. so the third side comes out to be 36-(12+9)=15 so the sides are...12,9,15. that's your answer..
Let the sides be x and y:- x+y = 40.2-17.42 => y = 22.78-x Using Pythagoras: x^2+(22.78)^2 = 17.42^2 As a quadratic equation: 2x^2++215.472-45.56x = 0 Solving the equation: x = 6.7 cm and y = 16.08 cm Check: 6.7+16.08+17.42 = 40.20 cm which is its perimeter
Let the sides be x and x-7 So using Pythagoras: x2+(x-7)2 = 172 => 2x2-14x-240 = 0 Solving the quadratic equation gives x a positive value of 15 Therefore sides are: 15 and 15-7 = 8 Perimeter: 17+15+8 = 40 cm
These are basically the steps: * Use the formula for the area of a triangle to calculate the height. * Use the height and half the base to calculate the lateral sides. Use the Pythagorean Theorem. (It helps to draw a sketch, to visualize the situation.) * Add the three sides to get the perimeter.