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How do you find the remaining legs of a 45 45 90 isosceles right triangle given a hypotenuse of 48 inches?
trig functions
sin(45o) = opposite/hypotenuse
sin(45o) = opp/48 inches
48 inches * sin(45o) = opposite
= 34 inches
===============you do other side with appropriate trig function
Update: Use Pythagoras.
Adj^2 + Opp^2 = Hyp^2
(For Isosceles right angles triangle Adj = Opp)
Therefore, Adj = Opp = Sqrt((Hyp^2)/2)
= 33.9
What else can I help you with?
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