The slope (m) = (delta y)/(delta x) m= (y2-y1)/(x2-x1) Given two points A(a,b) C(c,d) if A is the starting point (x1,y1) and C is the ending point (x2,y2) then m= (d-b)/(c-a) OR if C is the starting point then, m=(b-d)/(a-c) both will give you the same answer.
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To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
To find the slope (steepness, not height) of a line when given two points, do the following: Slope = (y2-y1)/(x2-x1), where (x1, y1) is one point, and (x2,y2) is the second point.
It's not possible because the given points would be a vertical line parallel to the y axis
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
Since the line is horizontal, the slope is zero.