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Q: How do you find theta for right triangle?

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The sine theta of an angle (in a right triangle) is the side opposite of the angle divided by the hypotenuse.

Using the angle (we'll call it theta) opposite the unknown side, you can find its length following this technique: 1. Draw a line from that angle to the midpoint of the unknown side, we'll call it B. This should be perpendicular to that side. 2. You have just formed two right triangles within your isosceles triangle. The hypotenuse of the right angle is your known side, we'll call it A. 3. Your angle theta has now been split in half. Calculate sin(theta/2). 4. Now you have: sin(theta/2) = (B/2)/A [Remember, sine = opposite over hypotenuse.] 5. Rearrange the equation to find B and plug in your numbers: B = 2A*sin(theta/2)

how to find the perimeter of a right angled triangle using the area

Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.

The 90 degree angle in a right angle triangle is opposite its hypotenuse.

Related questions

The answer depends on what theta represents!

when you have a right triangle and one of the two non-right angles is theta, sin(theta) is the side of the triangle opposite theta (the side not touching theta) divided by the side that does not touch the right angle

The sine of an angle theta that is part of a right triangle, not the right angle, is the opposite side divided by the hypotenuse. As a result, you could determine the hypotenuse by dividing the opposite side by the sine (theta)...sine (theta) = opposite/hypotenusehypotenuse = opposite/sine (theta)...Except that this won't work when sine (theta) is zero, which it is when theta is a multiple of pi. In this case, of course, the right triangle degrades to a straight line, and the hypotenuse, so to speak, is the same as the adjacent side.

The sine theta of an angle (in a right triangle) is the side opposite of the angle divided by the hypotenuse.

In a Right Triangle SINE Theta is equal to the: (Length of opposite side) / (Length of Hypotenuse).

Tangent (theta) is defined as sine (theta) divided by cosine (theta). In a right triangle, it is also defined as opposite (Y) divided by adjacent (X).

When placed next to any angle on a triangle, the theta symbol (Î¸) represents that missing angle.

if the triangle has one right angle in it

The cosine of theta is adjacent over hypotenuse, given a right triangle, theta not being the 90 degree angle, adjacent not being the hypotenuse, and theta being the angle between adjacent and hypotenuse. In a unit triangle, i.e. in a unit circle circumscribed with radius one, and theta and the center of the circle at the origin, cosine of theta is X.

If X and Y are sides of a right triangle, R is the hypoteneuse, and theta is the angle at the X-R vertex, then sin(theta) is Y / R and cosine(theta) is X / R. It follows, then, that X is R cosine(theta) and Y is R sin(theta)

One way would be as follows: Let b represent the length of the base, l the length of each of the two sides, and theta the angle between the base and the two sides of length l. Now drop a perpendicular line from each vertex at the top of the trapezoid to the base. This yields two right triangles and a rectangle in the middle. The height of each right triangle (as well as the height of the rectangle) equals l*sin(theta) [because sin(theta)=opposite/hypotenuse] and the length of the base of each right triangle is l*cos(theta). The base of the rectangle is b minus the lengths of the two right triangles. Area of the trapezoid=2*area of each right triangle+area of the rectangle=2*(1/2)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=b*l*sin(theta)-l2*sin(theta)*cos(theta)

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