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To solve the equation x^2 + y^2 = 13, you are looking for all possible pairs of real numbers (x, y) that satisfy this equation. This equation represents a circle centered at the origin with radius √13. The solutions to this equation are all the points on the circle with radius √13.
What else can I help you with?
Which equations correctly represents a circle centered at the origin with a radius of 5?
x2 + y2 = 25radius of 10?x2 + y2 = 100
How do you find the slope when given two points?
Points: (x, y) and (x2, y2) Slope = y2-y divided by x2-x
How do you find a midpoint between two points on a graph?
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
When using the slope formula does it have to be (y2-y1)(x2-x1) or can it be (y1-y2)(x1-x2)?
Oh, don't you worry, friend! When using the slope formula, whether you do (y2-y1)/(x2-x1) or (y1-y2)/(x1-x2), the answer will be the same! It's all about the difference in vertical and horizontal values, and as long as you stay consistent in your calculations, you'll find the slope just fine. Just trust your instincts and enjoy the process of solving the equation.
What is the equation for a semicircle?
x2+y2=r2, y>=0
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
How do you solve for slope from two points and a graph?
Points: (x1, y1) and (x2, y2) Slope: y1-y2/x1-x2
Find the centre and radius of the circle with equation x2 plus 2x plus y2 equals 12?
x2 + 2x + y2 = 12 (complete the square)(x2 + 2x + 1)+ y2 = 12 + 1(x + 1)2 + y2 = 13 (divide by 13 each element to both sides)(x + 1)2/13 + y2/13 = 1(x - -1)2/13 + (y - 0)2/13 = 1Thus, the center of the circle is (-1, 0) and its radius is 1.
How do you solve a slope problem?
Use the slope formula (y2-y1)/(x2-x1) and yes x2 is the x-value of your second x coordinate. Meanwhile y2 is the second y coordinate.
How do you solve the factoring different of two square?
X2 - Y2 = (X + Y)(X - Y)
The circle is centered at the origin and the length of its radius is 8 What is the circle's equation?
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
How do you draw a square using line command?
Line (x1, y1, x2, y1); Line (x2, y1, x2, y2); Line (x2, y2, x1, y2); Line (x1, y2, x1, y1);
Explain how do you write an equation of a line in standard form when two points on the line are given?
Th e two points are X1,Y1 and X2, Y2 slope, m, is y2-y1 divided by x2-x1 then standard form is y = mx +b plug in y2 for y and x2 for x and solve b or plug in y1 for y and x1 for x and solve b
How do you solve this problem it just says solve x2 plus 3y equals 7 3x plus y2 equals 3?
x2 + 3y = 7 3x + y2 = 3 3y = x2 + 7 y2 = -3x + 3 y = x2/3 + 7/3 y = ± √(-3x + 3) If you draw the graphs of y = x2/3 + 7/3 and y = ± √(-3x + 3) in a graphing calculator, you will see that they don't intersect, so that the system of the given equations has not a solution.
If xy equals x2 plus y2 plus 2xy?
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
What is the answer to (x plus y)2 x2 plus y2?
X2+y2=25 (x-8)2+y2 =41
How do you solve the equation. X2 plus y2 plus z2 - 4x plus 4y plus 2z plus 5 equals 0 x2 plus y2 plus z2 equals 4?
(2-r)e-rr
