To solve the equation x^2 + y^2 = 13, you are looking for all possible pairs of real numbers (x, y) that satisfy this equation. This equation represents a circle centered at the origin with radius √13. The solutions to this equation are all the points on the circle with radius √13.
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There is no single solution for x2 + y2 = 13, as there are an infinite number of corresponding values that could be plugged in for x and y.
x2 + y2 = 13 is a function that describes a circle. The circle would have a center point of 0, 0, and a radius of √13.
x2 + y2 = 25radius of 10?x2 + y2 = 100
Points: (x, y) and (x2, y2) Slope = y2-y divided by x2-x
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
Oh, don't you worry, friend! When using the slope formula, whether you do (y2-y1)/(x2-x1) or (y1-y2)/(x1-x2), the answer will be the same! It's all about the difference in vertical and horizontal values, and as long as you stay consistent in your calculations, you'll find the slope just fine. Just trust your instincts and enjoy the process of solving the equation.
x2+y2=r2, y>=0