It is isosceles.
It is isosceles.
No, they are not the same.
XZ
Not too sure of the question but if one side is 8 cm then its height must be 3 cm because:- Area of the triangle is: 0.5*8*3 = 12 square cm
(c2) / (2 cot A + cot B) = Area of Triangle ABC
find the area of abc a[2,3] c[6,0]
Since the sides of triangle are equal, the triangles are equilateral. Just for your information, in this question, we do not require the length of sides. It is just additional information. :) The area of equilateral triangle is: (√3)/4 × a², where a is the side of the equilateral triangle. For triangle ABC, area will be = (√3)/4 × a² (Let 'a' is the side of triangle ABC) Since, side of triangle PQR is half that of ABC, it will be = a/2 Therefore, area of triangle PQR = (√3)/4 × (a/2)² = (√3)/16 × a² Take the ratio of areas of triangle ABC and PQR: [(√3)/4 × a²] / [(√3)/16 × a²] = 4:1
We know that R = a/2sinA area of triangle = 1/2 bc sinA sin A = 2(area of triangle)/bc R = (a/2)*2(area of triangle)/bc R = abc/4*(area of triangle)
ABC angle is an angle,not a triangle!
It is isosceles.
It is isosceles.
The area of a triangle is base x height ... soo...... 9 x 16 =144 cm squared =)
triangle ABC with rigth at C
Triangle ABC is an equilateral triangle if and only if the lengths AB, AC & BC are all equal and the angles ∠ABC, ∠ACB & ∠CAB are all equal (to 60o).
The area enclosed by a chord is equal to the area enclosed by a segment minus the area enclosed by the triangle with the same corners as the segment. To visualise it, draw a circle and put a chord on it. Label the chord AB and the centre of the circle C. The area of sector AB equal to the area of sector ABC minus the area of triangle ABC.
No, they are not the same.