When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
it depends on where the sun is in the sky If the sun is at its highest point ur hsadows will be shorter but as the sun get slower your shadow will get longer
That depends on the height of the yardstick whose height has not been given.
To find the height of the tree, we can set up a proportion using the similar triangles formed by the tree and its shadow, and the person and their shadow. The ratio of the height of the tree to its shadow is the same as the ratio of the height of the person to their shadow. This gives us (height of tree)/(9 ft) = (6 ft)/(4 ft). Solving for the height of the tree, we get height of tree = (9 ft * 6 ft) / 4 ft = 13.5 ft.
By means of trigonometry if you know the angle of elevation or by comparing it with a nearby object if you know its height and shadow length.
The length of the shadow (on a flat, horizontal floor) depends on the height of the Sun. If the Sun is higher in the sky, the shadow will become shorter.
The length and position of a shadow depend on the angle of the light source, the distance between the object and the surface the shadow falls on, and the height of the object casting the shadow.
(1) One way would be to have a stick, stuck vertically into the ground. Measure the length of the shadow and the length of the stick. The actual height of the stick will be a ratio of the shadow's length. Then measure the length of the school's shadow. The height of the school in comparison with its shadow length will be same ratio as the height of the stick compared to its shadow length. You could use a tape measure for this. And possibly a calculator, which will make the calculation easier than doing it by long arithmetic or mental arithmetic. (2) Another way would be to use something that can tell you, from a short distance away from the school, the angle between the top of the school and the ground. A sextant can do this. It is more accurate than using a protractor. Using trigonometry and the distance from the building to where you are standing, you will be able to calculate the height of the school, because it will be at right angles to the line from you to the school. If you don't know trigonometry, method (1) will be easier.
By its shadow :) Then I measure mine shadow, or shadow of any object I know how high is.. and use proportion: HW/MH=WS/MS or HW=MH x WS/MS HW=wood height MH=mine height WS=length of wood shadow MS=length of mine shadow
The answer depends on: the height of the item casting the shadow, the location on earth, the time of year, and the inclination of the surface on which the shadow is cast.
The two triangles shown are similar triangles. Numerically, the ratio computed by dividing the length of any side of tower triangle by the length of the corresponding side of the walking stick (similar) triangle will be the same value. Therefore, when the length of the tower shadow is divided by the length of the walking stick shadow, that ratio will be the exactly same as the tower height divided by the walking stick height. (length of tower shadow)/(length of walking stick shadow) = (tower's height)/(walking stick height) tower's height = {(length of tower shadow)/(length of walking stick shadow)}*(walking stick height)
Using trigonometery if you know the length of its shadow and angle of elevation
I am not sure what you mean by "direct" - light tends to travel in a straight line. The length of the shadow depends on the length of the pole, and of the height of the Sun.
It's determined by the height (angle above the horizon) of the Sun, and the physical height of the object throwing the shadow. The height of the Sun at midday is 90 degrees minus the latitude plus the Sun's declination of the day, which varies by up to ±23.5 degrees through the year. The length of the shadow is the height of the object divided by the tangent of the Sun's height. Example, a 6 ft object at 50 degrees north on June 21: height of the object is 6 ft, divided by tan(90 - 50 + 23.5) so the shadow has a length of 3 ft.
It is zero: 0cm; 0mm A shadow has no height: length yes, but height no
It depends on the time of day because the angle of the sun will determine the shadow length