20 ft
15 cm for the diagonal.
The diagonal is 20.
Oh, dude, you're asking me to bust out some high school math here. So, like, to find the diagonal of a rectangle, you use the Pythagorean theorem. It's like a^2 + b^2 = c^2, where a and b are the sides of the rectangle. In this case, it's 12^2 + 16^2 = c^2. So, the diagonal would be the square root of 400, which is 20.
If the length of a rectangle is 12 and the width of the rectangle is 16, by the Pythagorean theorem we know that one diagonal is 20 units long. You can draw two diagonals within a rectangle, so the length of both diagonals together is 20+20 = 40 units.
The rectangle has dimensions of [ 12 x 3 ].
Using Pythagoras' theorem the length of the diagonal is 20 feet
A 9 x 12 rectangle has a diagonal of 15.
15 cm for the diagonal.
Any rectangle that measures 12-in x 13-in has a diagonal ofsqrt(122 + 132) = 17.692 inches (rounded)
Using Pythagoras, the diagonal is sqrt(122 + 162) = sqrt(144 +256) = sqrt(400) = 20 feet.
A rectangle has dimensions 7 ft x 12 ft. Which of the dimensions describe a rectangle that is similar to this rectangle?
The diagonal of a 12' x 24' rectangle is approx 26.8'.
The diagonal is 20.
That depends on the given dimensions which are not in the question.
Approximately 15.62 feet.
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
diagonal is 13 inch length of the rectangle of 12 and 5 inches sides