Oh, dude, you're asking me to bust out some high school math here. So, like, to find the diagonal of a rectangle, you use the Pythagorean theorem. It's like a^2 + b^2 = c^2, where a and b are the sides of the rectangle. In this case, it's 12^2 + 16^2 = c^2. So, the diagonal would be the square root of 400, which is 20.
The diagonal is 20.
17.8885'
20 ft
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
26.4 inches for the diagonal.
The diagonal is 20.
17.8885'
That would be 34 feet.
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle measuring 16 feet by 38 feet, the diagonal (d) can be calculated as (d = \sqrt{(16^2 + 38^2)}). This results in (d = \sqrt{(256 + 1444)} = \sqrt{1700} \approx 41.23) feet. Therefore, the diagonal measurement is approximately 41.23 feet.
Around 17.8. I did this with cossin, but check the answer with a calculator
Width is 16.
To find the diagonal measurement of a 12 x 16 wood deck, you can use the Pythagorean theorem. The diagonal (d) can be calculated as ( d = \sqrt{(12^2 + 16^2)} ). This gives ( d = \sqrt{(144 + 256)} = \sqrt{400} = 20 ) feet. Therefore, the diagonal measurement of the deck is 20 feet.
20 ft
Using Pythagoras' theorem the length of the diagonal is 20 feet
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
To find the diagonal of a rectangular face, you can use the Pythagorean theorem. For a rectangle with sides of 12 mm and 16 mm, the diagonal ( d ) is calculated as ( d = \sqrt{12^2 + 16^2} = \sqrt{144 + 256} = \sqrt{400} = 20 ) mm. Thus, the diagonal of the 12 mm-by-16 mm face is 20 mm long.
26.4 inches for the diagonal.