The number of diagonals is n(n-1)/2 - n substitute n=35 35(34)/2 - 35 = 560
100 diagonals * * * * * No, it is 0.5*10*(10-3) = 35
35 sides
It has 35 sides.
Ah, a triacontakaipentagon is a very special shape, friend. It has 35 sides, each one as unique as a happy little tree in a painting. Just imagine the joy and creativity that can bloom when you explore the beauty of such a geometric wonder. Don't be afraid to embrace its complexity and let your imagination dance freely with its harmonious angles and lines.
It will have ten sides
It has 10 sides because using the formula 0.5*(102-30) = 35 diagonals
It depends if the polygon is convex or concave but if it is a regular polygon it would have 560
It has 35 diagonals
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
There are 560 diagonals by using the diagonal formula
54 Diagonals. * * * * * A polygon with n sides has 1/2*n*(n-3) diagonals. So a decagon would have 1/2*10*7 = 35 diagonals. How the Community answer got 54 is anybody's guess!
The number of diagonals is n(n-1)/2 - n substitute n=35 35(34)/2 - 35 = 560
100 diagonals * * * * * No, it is 0.5*10*(10-3) = 35
1oo diagonals, because 1 side has 10 diagonals so 10 sides (10x10) = 100 diagonals! This is the correct answer..... a decagon has 35 diagonals. The equation for the this is D=n(n-3)/2 meaning diagonals = number of sides (N) multiplied by number of sides minus 3. and that number over 2. D=10(10-3)/2
35 diagonals
35 sides