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Q: How many lead balls each of radius 1 cm can be made from a sphere of radius 8 cm?

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The volume of a sphere is 4/3*pi*r3 So Vol8/Vol1 = 83/13 = 83 = 512

Gravity pulls with equal strength in all directions; therefore any variations from a spherical shape will lead to gravitational forces that bring the shape back into that of a sphere.

400 mg lead in each kilogram of soil.

Is this taking into consideration the dross content as the metal melts it oxides? and how much does the lead pipe weigh per foot?

The lead is held in place by tightening a knurled bolt. Open the bolt and remove the lead.

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It is: (4//3*pi*83) divided by (4/3*pi*13) = 512

The volume of a sphere is 4/3*pi*r3 So Vol8/Vol1 = 83/13 = 83 = 512

The density of lead is well known; you can look it up in any reference book on chemistry, or on the Internet. It is 11.34 grams per cubic centimeter, according to Wikipedia. But if you have a sphere that is only part lead, you can get the density of the sphere by weighing it, and dividing the weight by its volume. The volume of a sphere is 4/3 x pi x r ^ 3, where r is the radius of the sphere.

Atomic radius of Si is 111pm.Atomic radius of Pb is 175pm.Therefore lead has a larger atomic radius than silicon.

1.81 Å

They were made of lead

Lead balls. (Clay was used when lead was unavailable)

d=m/v v= (4/3)(pi)(r^3) set up equation for aluminum and lead 11.3*10^3=m/( (4/3)(pi)(ri^3)) 2.7*10^3=m/( (4/3)(pi)(ra^3)) solve for m. then set two equations equal to each other, since they have the same masses. finally, solve your new equations for ra/ri 11.3*10^3( (4/3)(pi)(ri^3)) =m 2.7*10^3( (4/3)(pi)(ra^3)) =m 11.3*10^3( (4/3)(pi)(ri^3)) = 2.7*10^3( (4/3)(pi)(ra^3)) 11.3*10^3/2.7*10^3 = (ra^3)/(ri^3) (11.3*10^3/2.7*10^3)^(1/3)=ra/ri

Charlie "Big Balls" Fink

IMDB will have your answer or google maybe.

5.94 milligrams.

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