16
It is: (4//3*pi*83) divided by (4/3*pi*13) = 512
Oh, dude, let me break it down for you. So, if the dog is tethered with a 20-foot lead and the path it walks is 45 feet, that's like a radian situation. The angle in radians would be like 45 feet divided by the radius of the circle, which is 20 feet, so it's around 2.25 radians. But hey, who's counting, right?
Meghan McGinty
false
If the lead digit cannot be zero then there are 9 x 9 x 8 x 7 = 4536 combinations. If the lead digit can be zero then there are, 10 x 9 x 8 x 7 = 5040 combination.
It is: (4//3*pi*83) divided by (4/3*pi*13) = 512
83 = 512
The volume of a sphere is 4/3*pi*r3 So Vol8/Vol1 = 83/13 = 83 = 512
The density of lead is well known; you can look it up in any reference book on chemistry, or on the Internet. It is 11.34 grams per cubic centimeter, according to Wikipedia. But if you have a sphere that is only part lead, you can get the density of the sphere by weighing it, and dividing the weight by its volume. The volume of a sphere is 4/3 x pi x r ^ 3, where r is the radius of the sphere.
A 12 gauge shotgun is determined by the fact that 12 solid balls of lead will fit into the bore of the gun and thus these 12 solid balls of lead will equal a pound. Likewise, it takes 20 solid balls of lead fitting into the barrel of a 20 gauge shotgun to equal a pound. 10 solid balls of lead that equal a pound fitting in the bore of a shotgun would make that a 10 gauge, like wise a 16 gauge and a 28 gauge. There have been 8 gauge guns but an exception to all this is the 410 which is not a gauge but a caliber. The caliber of a 410 shotgun is .410 or there a bouts. Some research on your part will help you understand more if your desire but you can see that smaller balls make gauges with larger numbers and therefore, a larger number gauge like 20 will shoot shells that are smaller in diameter than those shot in a 12 gauge.
d=m/v v= (4/3)(pi)(r^3) set up equation for aluminum and lead 11.3*10^3=m/( (4/3)(pi)(ri^3)) 2.7*10^3=m/( (4/3)(pi)(ra^3)) solve for m. then set two equations equal to each other, since they have the same masses. finally, solve your new equations for ra/ri 11.3*10^3( (4/3)(pi)(ri^3)) =m 2.7*10^3( (4/3)(pi)(ra^3)) =m 11.3*10^3( (4/3)(pi)(ri^3)) = 2.7*10^3( (4/3)(pi)(ra^3)) 11.3*10^3/2.7*10^3 = (ra^3)/(ri^3) (11.3*10^3/2.7*10^3)^(1/3)=ra/ri
Lead is a crystalline solid at room temperature and pressure.
Atomic radius of Si is 111pm.Atomic radius of Pb is 175pm.Therefore lead has a larger atomic radius than silicon.
Yes, lead hydroxide is a solid compound at room temperature.
solid
Lead is a solid at room temperature and pressure.
Lead is a solid at room temperature. It has a melting point of 327.5°C and a boiling point of 1749°C.