It is: (4//3*pi*83) divided by (4/3*pi*13) = 512
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Sphere: 4/3*pi*r3 Tetrahedron: s3*sqrt(2)/12 Cube: s3 Octahedron: s3*sqrt(2)/3 Dodecahedron: s3*[15+7*sqrt(5)]/4 Icosahedron: s3*5/12*(3+sqrt(5) where r is the radius and s is the length of each edge.
The question is stated as if in the presence of excessive background noise.If we're talking about a circle, and if '1,017.36' is its area, then we can find the radius like this:1,017.36 = pi R2Divide each side by pi:1,017.36 / pi = R2Take the square root of each side:R = sqrt( 1,017.36 / pi ) = 17.99544(rounded)=====================================We're guessing that the given radius was 18, and some arithmetic errors crept induring the process of finding the area.If the radius is 18, thenArea = pi R2 = 324 pi = 1,017.88 (rounded)Working backward from 1,017.88, we would get 18.00004 for the radius.
Pythagoras! Two sides of the triangle must each be equal to the radius, ie 3 so Hypotenuse = sqrt(3^2 + 3^2) =sqrt 18 = 4.243
83 = 512
That depends. What is that "square root of 354" ? Is it the circumference ? Diameter ? Area of the circle ? Area of the sphere ? Volume of the sphere ? The radius is different for each one.
The moment of inertia of a solid sphere is derived by integrating the mass of the sphere over its volume, taking into account the distance of each mass element from the axis of rotation. This integration results in the formula for the moment of inertia of a solid sphere, which is (2/5) mass radius2.
Volume of the sphere varies as the cube of the radius.Tripling the radius increases the volume by a factor of (3)3 = 27.It takes 27 spherical volumes with radius 'r' to fill one spherical volume with radius '3r'.
The volume of a sphere is 4/3*pi*r3 So Vol8/Vol1 = 83/13 = 83 = 512
If the radius of each tennis ball is 3cm, then the diameter of each ball would be 6 centimeters. And since there are 3 balls, the height of the cylinder would be 18 centimeters.
£47.00 each
No, a hollow sphere can hold a larger electric charge compared to a solid sphere of the same diameter because the charge resides on the outer surface in both cases. In a hollow sphere, the charge distributes uniformly on the outer surface, allowing it to hold more charge without experiencing as much repulsion between like charges as a solid sphere.
No, the charge of a hollow sphere and a solid sphere of the same diameter will be the same as long as they are both made of the same material. In both cases, the charge resides on the outer surface of the sphere due to electrostatic repulsion.
Each polyhedron is a kind of solid object. Some solid objects -- for example, a sphere or a torus -- are not polyhedra, but every solid object can be closely approximated with a polyhedra.
No, the volume formula is not universal for all figures. Different shapes and objects have different formulas to calculate their volume based on their unique dimensions and properties. Each shape requires its own specific formula to accurately determine its volume.
The volume of a sphere can be calculated as:volume = (4/3) x pi x radius cubed Simply replace the given radius, and do the calculations.