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In a Euclidean plane, only one.
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Prove that the perpendicular at the point of contact to the tangent to a circle passes through the center?
Draw a circle with centre O. draw a tangent PR touching circle at P. Draw QP perpendicular to RP at point P, Qp lies in the circle. Now, angle OPR = 90 degree (radius perpendicular to tangent) also angle QPR = 90 degree (given) Therefore angle OPR = angle QPR. This is possible only when O lies on QP. Hence, it is prooved that the perpendicular at the point of contact to the tangent to a circle passes through the centre. Answer By- Rajendra Meena, Jaipur, India. email: rajendra.meena21@gmail.com
Joaquin is constructing the perpendicular bisector of line AB. What should be his first step?
Place the point if the compass on point B and draw an arc across AB.
How do you draw two parallel lines using only a straightedge and a protractor?
Draw a line. Draw a perpendicular to that line then a perpendicular from that one.
Which term describes the point where the perpendicular bisector of the three sides of a triangle intersect?
It is the circumcentre, the unique point from which you can draw a circle (the circumscribed circle) which passes through all three vertices.
How can I draw a quadrilateral that has exactly two perpendicular sides?
what quadrilateral has exactly two perpendicular sides.
How many perpendiculars can we draw to a line from a given point outside the line?
In a Euclidean plane, only one.
How do you find radius of a circle?
Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.
The number of normals to the parabola from a point which lies outside?
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
What is the definition of distance from point to line?
It the point is on the line the distance is 0. If the point is not on the line, then it is possible to draw a unique line from the point to the line which is perpendicular to the line. The distance from the point to the line is the distance along this perpendicular to the line.
Prove that the perpendicular at the point of contact to the tangent to a circle passes through the center?
Draw a circle with centre O. draw a tangent PR touching circle at P. Draw QP perpendicular to RP at point P, Qp lies in the circle. Now, angle OPR = 90 degree (radius perpendicular to tangent) also angle QPR = 90 degree (given) Therefore angle OPR = angle QPR. This is possible only when O lies on QP. Hence, it is prooved that the perpendicular at the point of contact to the tangent to a circle passes through the centre. Answer By- Rajendra Meena, Jaipur, India. email: rajendra.meena21@gmail.com
How do you draw a chord when the perpendicular distance is given?
Using the fact that the centre of a chord is at right angles to the radius
Draw two intersecting lines but not perpendicular?
draw two intersecting lines that are not perpendicular
Joaquin is constructing the perpendicular bisector of line AB. What should be his first step?
Place the point if the compass on point B and draw an arc across AB.
How do you draw two parallel lines using only a straightedge and a protractor?
Draw a line. Draw a perpendicular to that line then a perpendicular from that one.
Construct a circle with a radius r. mark a point on the circle. construct a tangent thourgh this point.?
1) draw the circle with a radius r and the center at O. 2) mark a point, A, on the circle 3) draw a line from O to A and beyond to point B, a little longer than the radius 4) draw a perpendicular bisector at point A using line OB 5) the perpendicular bisector is the tangent at point A In case, you forgot about drawing the perpendicular bisector. Here is the procedure: a) use your compass and mark equidistant points C and D from point A on line OB (make the length slightly less than half the radius); one point should be outside the circle and the other within. b) use your compass and draw an arc from point C and then from point D, with the arc radii being identical and about as long as the circle radius; the two arcs should intercept at two locations, E and F, one on each side of line OA. c) join points E and F to form the perpendicular bisector of line CD ===============================
joaquin is constructing the perpendicular bisector of ab. what should be his first step?
Place the point if the compass on point B and draw an arc across AB.
How do you find the altitude outside of a triangle?
The altitude of a triangle is the distance from the line containing the base to the vertex. Draw the base and continue on outside of the triangle. Measure perpendicular from that line to the vertex.
