Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.
It the point is on the line the distance is 0. If the point is not on the line, then it is possible to draw a unique line from the point to the line which is perpendicular to the line. The distance from the point to the line is the distance along this perpendicular to the line.
draw two intersecting lines that are not perpendicular
Suppose you are given a bangle and you are supposed to measure the circumference. OK? First place it on a paper fixed to a board. Using a fine pencil mark its boundary outer if outer circumference is required. Now draw one chord. Mark AB. Using protractor draw a line perpendicular to the chord at B. Name as BC. Join AC. Measure AC. Multiply AC by 3.14. You would get the required circumference nearly to the accurate one.
When you draw a circle in math, and you draw a triangle inside of it, 2 of the lines should be the radius of the circle, and the third (bottom) line that is not the radius is the chord.
Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.
Draw a chord, then construct a line perpendicular to the center of the chord; it passes through the center of the circle. Do this again with a different chord and the intersection of the two perpendicular lines is the center of the circle.
Draw any two chords.Draw the perpendicular bisectors of these chords.Find their point of intersection.That is the centre.Use Pythagoras to calculate the distance from the centre to either end of any chord.
It the point is on the line the distance is 0. If the point is not on the line, then it is possible to draw a unique line from the point to the line which is perpendicular to the line. The distance from the point to the line is the distance along this perpendicular to the line.
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
-- Draw any two random chords of the circle. -- Construct the perpendicular bisector of each chord. -- The perpendicular bisectors intersect at the center of the circle. All of this can be done with a compass, an unmarked straight-edge, and a pencil.
In a Euclidean plane, only one.
draw two intersecting lines that are not perpendicular
Suppose you are given a bangle and you are supposed to measure the circumference. OK? First place it on a paper fixed to a board. Using a fine pencil mark its boundary outer if outer circumference is required. Now draw one chord. Mark AB. Using protractor draw a line perpendicular to the chord at B. Name as BC. Join AC. Measure AC. Multiply AC by 3.14. You would get the required circumference nearly to the accurate one.
Draw a line. Draw a perpendicular to that line then a perpendicular from that one.
You have points A, B, and C. Using a compass and straight edge, find a perpendicular bisector of AB (that is, a line that is perpendicular to AB and intersects AB at the midpoint of AB. Next, find a perpendicular bisector of BC. The two lines you found will meet at the center of the circle.
well,first the radius is half of the chord. Radius is the distance from the circle centre to the chord end. The chord is the line joining the ends of the arc. Draw this line. Call the distance from the arc of the circle at its deepest point to the mid point of the chord "c". If extended, this line will go throught the centre of the circle. Call half the length of the chord "y". Then the properties of circles and chords is that c(d-c)=y2 where d is the circle diameter, so that d = y2/c + c. And then radius is half that.