There's 30 yard bolts and other sizes it's 54" width and in feet it would be 30x 3 = 90 feet I can make it easy for someone you get 10 sheets out of a 30 yard Tif it's eight foot ceilings.
Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
The statue would be eight meters tall. Set up the ratio 40/x = 30/6 Multiple both sides by 6x to get 40*6 = 30x or 240 = 30x Divide both sides by 30 to get 8=x.
We know that the sum of a polygon's exterior angles, one at each vertex, equals 360 degrees. So at each angle extended from each side there is an angle of 30 degrees. If x= number of sides, then 30x = 360. Divide by 30 and x = 12.
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sqrt(30x) cannot be simplified. It is approx ±5.4772*sqrt(x).
There's 30 yard bolts and other sizes it's 54" width and in feet it would be 30x 3 = 90 feet I can make it easy for someone you get 10 sheets out of a 30 yard Tif it's eight foot ceilings.
15 x 30 x 15 feet holds 50,493.5 gallons.
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30 employees, 42 square feet allowed 30 x 42 = 1260 square feet of space 5 more employees, 42 square feet allowed 5 x 42 = 210 square feet of space needed current space is 1260 needed space is 210 1260 - 210 = 1050 square feet of space left The 30 employees are left with 1050 square feet of space 30x = 1050 x = 35 square feet left for each employee beginning space = 42 ending space = 35 42 - 35 = 7 square feet of less work space
30x = 30,000
That's 35 - 30x. The GCF of 35 and 30x is 5.
This is a nonsense question; feet is a measure of distance, years is a measure of time.
The GCF is 5.
The GCF of 24x and 30x is 6x.
-30x=6.3 x=-.21