Either
12,14,16,or18
I think 18.
* * * * *
The correct answers is 4. You can draw only 3 diagonals from one vertex.
4 are formed
From each vertex to its opposite vertex. These will be centered on a shared point at the center of the hexagon. Each complete line will be a line of symmetry for the hexagon.
13 The correct answer is 12. From any one vertex, you can draw a diagonal to all but 3 vertices: the vertex itself and the next vertex on either side of your vertex (these would be sides of your shape, not diagonals).
n-3 diagonals. Of the n vertices of the polygon, you cannot draw diagonals to the two adjacent vertices since these are sides of the polygon and so not diagonals. And you cannot draw a diagonal from a vertex to itself. So those are three vertices that are ruled out, leaving n-3.
To divide a hexagon into three equal parts, you can draw lines from each vertex to the opposite side's midpoint, creating six smaller triangles within the hexagon. Then, draw a line connecting the midpoints of two opposite sides. This line will divide the hexagon into three equal parts, each containing two of the smaller triangles. This method ensures that each part has an equal area and maintains the symmetry of the hexagon.
4.
fourteen. If you draw if diagonals from one vertex there are 14. fourteen. If you draw if diagonals from one vertex there are 14.
four (4)
18
The answer would be 18.
33 triangles
It is: 8-2 = 6 triangles
Five of them
4 are formed
You can draw 9 diagonals inside a hexagon.
Look at it the other way. Draw a hexagon, and draw two horizontal lines, in each case from one vertex to another one. That way you'll see how to divide the hexagon into a rectangle (not necessarily a square), and two triangles - which, of course, you can combine again to form the hexagon.
There are 5 diagonals