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In a hexagon, each vertex can connect to all other non-adjacent vertices to form diagonals. Since a hexagon has 6 vertices, each vertex can form diagonals with the other 4 non-adjacent vertices. Therefore, each vertex of a hexagon can create 4 diagonals. This results in a total of 6 vertices x 4 diagonals = 24 diagonals in a hexagon.
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How many diagonals does a hexagon have one vertex?
None. By definition a diagonal goes from one vertex to another vertex and so each diagonal MUST have two vertices.
If a circle is inscribed in a hexagon which of the following must be true?
A. The hexagon is circumscribed about the circle . D. Each vertex of the hexagon lies outside the circle . E. The circle is tangent to each side of the hexagon .
A hexagon can be divided into how many triangles by drawing all of the diagonals from one vertex?
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
How many diagonals can be drawn from each vertex of an octagon?
it really isn't hard 5
How do you find diagonals in a polygon?
Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2
