4 x 6 x .75 = 18 cu ft of sand
As you did not specify a depth, I can not provide an answer.
9.26 cubic yards for every inch of depth.
use a known volume container to measure a quantity = 200 x (the depth you want the sand).
how much 1" rock will I need to fill in a hole 20' long, 2' wide' and about 2' deep
The soil type and amount of compaction will cause the amount to vary, but in general, using Med PI common fill with minimum compaction will require about 41,000 cubic yards to raise 5 acres 4' in elevation
72 cubic feet
32 cubic ft.
To calculate the volume of sand needed to fill a sandbox measuring 6 feet by 6 feet to a depth of 12 inches (1 foot), first convert the dimensions to feet. The volume is then 6 ft × 6 ft × 1 ft = 36 cubic feet. Therefore, you will need 36 cubic feet of sand to fill the sandbox.
To calculate the volume of sand needed to fill the sandbox, multiply its dimensions: 50 ft (length) × 1 ft (depth) × 1 ft (width) = 50 cubic feet. Therefore, you will need 50 cubic feet of sand to fill the sandbox.
To determine the amount of sand needed to fill a 6' x 6' sandbox, you also need to know the depth of the sandbox. Assuming a standard depth of 1 foot, the volume would be 6' x 6' x 1' = 36 cubic feet. Since a cubic yard contains 27 cubic feet, you'd need approximately 1.33 cubic yards of sand to fill the sandbox.
It will take 72 sq. ft. of sand. Or 2.66 sq. yds. That will fill the box even.
All you have to do is find the maximum volume of your sandbox. To do this, multiply the length (6 ft.) by the width (6 ft.) by the depth (10 ft.). 6 x 6 x 10 = 360 cubic feet This is if you want to fill the sandbox to the brim. If you want something about half the depth so that the sand isn't falling out everywhere, you just multiply: 6 x 6 x 5 = 180 cubic feet
192
Volume of sand required = 7 ft * 7 ft * 1/6 ft = 49/6 cubic feet = 8.166... cubic ft.
The answer will depend on the depth to which the area is covered.
15 * 5 * 0.5 = 37.5 cu ft. or 1.39 cu yards.
5300 gallons