72 cubic feet
10 2/7 hours
Assuming the jug was empty, it would require 1 litre. If the jug contained any amount of water, the requirement would be 1 litre minus however much was in the jug already.
if you mean a 30 foot diameter circle, then pi x 152 x 3 = 2119.5 cubic feet of dirt
1 foot = 12 inches 20 ft * 7 ft can be expressed as 240 inches * 84 inches, then 240 in * 84 in * 2 in = 40320 inches cubed or 3360 cubic feet
The answer depends on the depth to which the area is covered.
32 cubic ft.
4 x 6 x .75 = 18 cu ft of sand
It will take 72 sq. ft. of sand. Or 2.66 sq. yds. That will fill the box even.
All you have to do is find the maximum volume of your sandbox. To do this, multiply the length (6 ft.) by the width (6 ft.) by the depth (10 ft.). 6 x 6 x 10 = 360 cubic feet This is if you want to fill the sandbox to the brim. If you want something about half the depth so that the sand isn't falling out everywhere, you just multiply: 6 x 6 x 5 = 180 cubic feet
192
Volume of sand required = 7 ft * 7 ft * 1/6 ft = 49/6 cubic feet = 8.166... cubic ft.
The answer will depend on the depth to which the area is covered.
15 * 5 * 0.5 = 37.5 cu ft. or 1.39 cu yards.
5300 gallons
(3 x 2 x depth of the hole in feet) cubic feet
12.5 cubic feet
Depends on the depth of the pool