It is k times the perimeter of EFGH where k is the constant ratio of the sides of ABCD to the corresponding sides of EFGH.
It is k times the perimeter of eh where k is the constant ratio of the sides of abcd to the corresponding sides of efgh.
It is k times the perimeter of efgh, where k is the constant of proportionality between the sides of abcd and the corresponding sides of efgh.
The question cannot be answered without information about the relative sizes of the two polygons.
Wonderful! If you had told us something about polygon efgh, and mentioned some small tidbit of information regarding the ratio of similarity, we might have had a fighting chance. The question is a lot like asking: "Bob is older than Jim. How old is Bob ?"
It is k times the perimeter of EFGH where k is the constant ratio of the sides of ABCD to the corresponding sides of EFGH.
It is k times the perimeter of eh where k is the constant ratio of the sides of abcd to the corresponding sides of efgh.
It is k times the perimeter of efgh, where k is the constant of proportionality between the sides of abcd and the corresponding sides of efgh.
4
The question cannot be answered without information about the relative sizes of the two polygons.
Wonderful! If you had told us something about polygon efgh, and mentioned some small tidbit of information regarding the ratio of similarity, we might have had a fighting chance. The question is a lot like asking: "Bob is older than Jim. How old is Bob ?"
12
It is the scale factor times the length of ad.
2.50
touch "abcd efgh" touch 'abcd efgh' touch abcd\ efgh are three possibilities, given that you use a Linux shell. Otherwise, it may depend on the specifics of the software (e.g. libreoffice, emacs, firefox...), usually you can do it staghtforwardly when saving a file.
It is k times the length of Ad where k is the constant of proportionality between the two shapes.
If each side of ABCD is four then the midpoints divide each side in half, or two. If you draw the square efgh, each side is 2 times square root 2 from Pythagorean theorem. sqrt (2 sq + 2 sq) =2 square root 2. the area is the sides squared or 2 root 2 times 2 root 2 = 4 x 2 = 8