LET angle 1= 2x
angle 2= x
"find the value of x"
angle1 + angle2 = 90
2x + x = 90
3x = 90
3
X = 30
"subtitute the X with the equation"
angle1 = 2x
2(30)
60
angle2 = 30
The smaller angle is 20 degrees and the larger is 70 degrees. Complementary angles total 90 degrees. Let's call the smaller angle A. The other angle is 3A + 10. The sum of both angles is 90, so 4A +10 = 90, 4A = 80, A = 20. The larger angle is 3(20) + 10 = 70.
A+b=180 x+2x=180 3x=180 x=60
72, 72, 36
X=30 degrees
First angle=X Second angle=4x Third angle=5X-45 Since the angles of a triangle always = 180o x+(4X)+(5X-45)=180o 10X-45=180 10X=225 X=22.5 Therefore. . . First Angle=X=22.5o Second Angle=4X=90o Third Angle=5X-45=67.5o
The smaller angle is 20 degrees and the larger is 70 degrees. Complementary angles total 90 degrees. Let's call the smaller angle A. The other angle is 3A + 10. The sum of both angles is 90, so 4A +10 = 90, 4A = 80, A = 20. The larger angle is 3(20) + 10 = 70.
To find the measure of an angle, you need to know the size of the entire angle and the other angles within the angle. Then, you subtract the smaller, known angles from the entire, large angle and you should get the measure of the missing angle.
Congruent angles have the same measure. congruent Kenpachi54 improve answer: Actually, angles don't have to be congruent just to have the same angle measurements A has a right angle is 90 degrees. even if there is a small right angle and a large right angle you know they are both 90 degrees because ALL right angles are 90 degrees, so there is really no name for it.
Let's assume the measure of the first angle is x degrees. The second angle is one-third as large as the first, so its measure is (1/3) * x = x/3 degrees. The third angle is two-thirds as large as the first, so its measure is (2/3) * x = 2x/3 degrees. Therefore, the measures of the angles in the triangle are x degrees, x/3 degrees, and 2x/3 degrees.
Complimentary angles are two angles that add up to 90o. It the sum of two angles is 90o, and one is twice as big as the other, then we can make up a little equation to solve for that larger angle (a). It might look like this: 90o = a + ( a / 2 ) As our larger angle (a) was said to be twice as large as our smaller angle, our smaller angle (a/2) is half as large as the larger angle. 90o = 3a / 2 180o = 3a a = 180o / 3 = 60o Our mystery angle is a 60o angle. The smaller one is 30o. The larger angle is twice the smaller, and they two sum to 90o. Our work checks.
90 degrees. This is an isosceles right triangle, standing on its hypotenuse.
A+b=180 x+2x=180 3x=180 x=60
A = 60 B = 20 C = 140 This can have a large number of answers.
72, 72, 36
X=30 degrees
Let the first angle be x the second angle be 4x and the third angle be 80+4x+x: x+4x+80+4x+x = 180 Collect like terms: 10x = 180-80 10x = 100 x = 10 Therefore the measure of the second angle is 40 degrees.
No, they both have right-angles.