Let's denote the width of the rectangle as x feet. Given that the length is eight feet more than the width, we can represent the length as x + 8 feet. The formula for the area of a rectangle is length multiplied by width, so we have the equation (x + 8) * x = 345. By solving this quadratic equation, we find that the width is 15 feet and the length is 23 feet.
A = lw Area of a rectangle = length times width
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
It is the area of the rectangle which is length times width
Length times width gives the area of a rectangle. The rectangle with a length of 38 and a width of 28 has an area of 1064 square units.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The area of a rectangle is found by length times width.
For a rectangle or square, Area = Length * Width So Length = Area / Width.
A = lw Area of a rectangle = length times width
length times width
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
It is the area of the rectangle which is length times width
Length times width gives the area of a rectangle. The rectangle with a length of 38 and a width of 28 has an area of 1064 square units.
length times width equals the area of a rectangle. length times width equals the area of a rectangle. area
Area of rectangle divided by its length = width of rectangle
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the area of a rectangle = length x widthwe can rearrange this to give uslength of a rectangle = area/ width
area of a rectangle = length * width. Rearranging, we have width = area / length. Therefore, the width of the rectangle = 31.2 [m2] / 6 [m] = 5.2 [m] ========================