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If is both the altitude and median of triangle ABC then triangle ABC is .?
It is isosceles.
If is both the altitude and median of triangle ABC then triangle ABC is?
It is isosceles.
what- triangle ABC?
XZ
Triangle ABc has right angle which is angle ABC and a line is formed called line segment abd draw this figure in order to solve problem below if line segment ac is perpendiclar to linesegment cb an?
35 degrees
The parallelogram ABCD is a rhombus what type of triangle is ABC?
isosceles triangle
What type of triangle is angle ABC?
ABC angle is an angle,not a triangle!
If is both the altitude and median of triangle ABC then triangle ABC is .?
It is isosceles.
If is both the altitude and median of triangle ABC then triangle ABC is?
It is isosceles.
Triangle ABC angle A is 60 what is angle C?
triangle ABC with rigth at C
Triangle ABC is an equilateral triangle?
Triangle ABC is an equilateral triangle if and only if the lengths AB, AC & BC are all equal and the angles ∠ABC, ∠ACB & ∠CAB are all equal (to 60o).
I’m triangle ABC?
A is a triangle
What are the kinds of triangle according the measure of angle?
Angle in triangle abc measure 27, 73 and 80, what kind of triangle is abc
Which side lengths form a triangle that is similar to triangle ABC?
Any triangle whose sides are in the same ratio with the corresponding sides of ABC.
How do you solve this geometry proof?
Given ABE, ADC, BD bisescts angle ABC and BD is parallel to EC prove: Triangle EBC is isoceles
what- triangle ABC?
XZ
If in ABC B is equal to C what kind of triangle is ABC?
Triangle ABC would be an isosceles. An isosceles triangle is defined as having two sides of equal length. This would also mean, then, that two angles in the triangle are also the same.
Triangle ABC has two sides that measure 12 inches and 16 inches. which could be the measures of the corresponding sides of a triangle that is similar to triangle ABC?
One pair of corresponding sides of a triangle that are similar to triangle ABC are 6 inches and 8 inches. However, there are multiple answers to this question.
