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In triangle ABC C is 62 degrees a is 10 and b is 15 find side c?
Wiki User
∙ 15y ago
In this specific example one would use the Law of Cosines. The Law of Cosines is defined as:
* a2 = b2 + c2 - 2bc(cos(A)) In this case, we need to switch the formula to fit our sides:
* c2 = a2 + b2 - 2ab(cos(C)) Now, we just input are given numbers into the equation:
* c2 = (10)2 + (15)2 - 2(10)(15)cos(62o) Make sure your calculator is in degree mode when solving this equation.
* c2 = (100) + (225) - (300)cos(62o) * c2 = 325 - 140.84 * c2 = 184.16 (Square root each side)
* c = 13.57
Wiki User
∙ 15y ago
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