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Yes its height is the same as its radius

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Q: Is the height of a hemisphere the same as the radius?
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A cone surmounted by a cylinder surmounted by a hemisphere find its volume hemisphere 6m in height cylinder 7m in height cone 5m in height not given the radius or diameter?

The radius IS given, since height of hemisphere = radius of hemisphere!


What is the radius of a hemisphere dome with a height of 32?

The radius is 32 because the height of the hemisphere (which is half of a sphere) is the same thing as the radius (which is half the length of the diameter); the radius is the distance from the center to any point on the edge or surface of the circle/sphere.


What is the volume of water in a hemisphere with given radius of hemisphere and height of water?

Can not be done without the 'Given' radius and height.


How do you calculate this a right circular cone is inscribed in a hemisphere so that base of cone coincides with base of hemisphere what is the ratio of the height of cone to radius of hemisphere?

Suppose the radius of the sphere is R. The base of the cone is the same as the base of the hemisphere so the radius of the base of the cone is also R. The apex of the cone is on the surface of the hemisphere above the centre of the base. That is, it is at the "North pole" position. So the height of the cone is also the radius of the sphere = R. So the ratio is 1.


Is the volume formula universal for all the figures?

No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3 No because, Sphere : (4 * pi * cube of the radius)/3 Hemisphere: (2 * pi * cube of the radius)/3 Cylinder: pi * (square of the base radius) * height Cone: (pi * square of base radius * height)/3


How do you calculate this- a right circular cone is inscribed in a hemisphere so that base of cone coincides with base of hemisphere what is the ratio of the height of cone to radius of hemisphere?

The vertex of the cone would reach the very top of the sphere, so the height of the cone would be the same as the radius of the sphere. Therefore the ratio is 1:1, no calculation is necessary.


What is the volume of a hemisphere and a cone?

Volume of Hemisphere = 2/3 * Pi * (radius)^3 Volume of Cone = 1/3 * Pi * (radius)^2 * height where Pi = 22/7 (approx)


If the volume of the hemisphere is 1152pi then what is the radius?

The radius of the hemisphere is 12 units.


What is the volume of a hemisphere with a radius of 3?

A hemisphere with a radius of 3 has a volume of 56.55 units3


What is the volume of a hemisphere if the radius is 2?

A hemisphere with a radius of two has a volume of 16.8 units3


How do you keep the volume of a cylinder the same if the radius quadruples?

Reduce its height


What dimensions do you need for a cylinder to have the same volume as a sphere with a radius of 7?

Volume sphere = 4/3 πr³ = 4/3 π 7³ = 1372π/3 Volume cylinder = πr²h = 1372π/3 → r²h = 1372/3 So as long as the radius of the cylinder is related to its height by: radius = √(1372 / (3×height)) or height = 1372 / (3×radius²) You can have a cylinder of almost any size you want. Example sizes: radius 1, height 1372/3 radius 7, height 28/3 height 7, radius 14/√3 height 28/3, radius 7 height 49, radius √(28/3)