Perimeter of rectangle: 2*(7+6) = 26 m
The equation of a line through point (x0, y0) with gradient m is given by:y - y0 = m(x - x0)The gradient (m) of a line between two points (x0, y0) and (x1, y1) is given by:m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0)→ The equation of the line between (11, 13) and (17, 19) is given by:y - 13 = (19-13)/(17-11) (x - 11)→ y - 13 = 6/6 (x - 11)→ y - 13 = x - 11→ y = x + 2and its gradient is m = 1.The gradient (m') of a line perpendicular to a line with gradient m is such that mm' = -1, ie m' = -1/m→ The gradient of the perpendicular line to the line between (11, 13) and (17, 19) has gradient m' = -1/1 = -1.The perpendicular bisector goes through the point midway between (11, 13) and (17, 19) which is given by the average of the x and y coordinates: ((11+17)/2, (13+19)/2) = (14, 16)Thus the perpendicular bisector of the line joining (11, 13) to (17,19) is given by:y - 16 = -1(x - 14)→ y - 16 = -x + 14→ y + x = 30Which in its general form is: x+y-30 = 0
Perimeter: 32 m Area: 60 m
3*2 = 6 square m
169m2 is the answer
6 + m = 16 m = 16 - 6 = 10
(m + 6)(m + 1)
11m + 13 = m + 23 10m + 13 = 23 10m = 10 m = 1
42 ft (13 m).
13=m+2m=11
17 + 6 + m
4m+9+5m-12=42 9m=45 m=5
13
16+7m16+7(42)16+294310
If: -6+m = 0 Then: m = 6
5m - 6 + m + 10 = 6m + 4
m(m - 6) = 91 m(m) + m(-6) = 91 m2 - 6m = 91 subtract 91 from both sides m2 - 6m - 91 = 0 since -91 = (-13)(7) and -13 + 7 = -6, then (m + 7)(m - 13) = 0 m + 7 = 0 or m - 13 = 0 m = -7 or m = 13