Area of a possible rectangle: 9 times 2 = 18 square m
A=m*h m=(a+b)/2
Area = pi*82 = 201.062 square m and rounded to 3 dp
To find the area of a triangle, you use the formula: Area = 1/2 * base * height. Plugging in the values, we get Area = 1/2 * 18 m * 20 m = 180 square meters. Therefore, the area of the triangle is 180 square meters.
area of rectangle = l * b area = 8 * 5 =40 m ^2 ( 1 m=100 cm 500cm= 5 m)
the area of an mxm square is m^2. For example, a 3x3 square has area 3^2 or 9
Area of a triangle = 1/2 * base * height = 1/2*3*5 = 7.5 square metres.
The Surface area is given by 2(lb+bh+hl) in this case, l=5m b=3m h=2m therefore the Surface area, sa=2(5*3+3*2+2*5) =2(15+6+10) =2(31) sa =62m2
Area of a cirlce = pi*r^2. A = pi*3^2 = 9*pi = 28.2743 m^2.
( m^2 - m - 3 ) + ( m - 4 ) = m^2 - m - 3 + m - 4 = m^2 - 7Answer: m^2 - 7
If all the vertices of the regular hexagon are joined to the centre of the hexagon, 6 equilateral triangles are created: the area of the hexagon is 6 times the area of one of these triangles. If the length of the side of the hexagon is m, then the length of each of the sides of these triangles is also m. Using Pythagoras the height of these triangles can be found to be m x sqrt(3)/2. Thus the area of the hexagon = 6 x area triangle = 6 x (m x m x sqrt(3)/2) / 2 = (3/2) sqrt(3) m2 ~= 2.6 x square of length_of_side
Area of a rectangle = length of base x height Area of a triangle = (length of base x height)/2 A.............................................. B mmmmmmmmmmmmmmmmmmm m.............................................. m m ..............................................m m.............................................. m m.............................................. m m.............................................. m m ..............................................m m.............................................. m mmmmmmmmmmmmmmmmmmm C ..............................................D Area of ABCD = AB x AC Area of ABCD = (AB X AC)/2 Then Area of ABCD = 2 Area of ABC
If they have the same radius then it is: 3 to 2
A hexagon with sides of 60 m will have an area greater than 0 m2 and less than or equal to 5400√3 m2 (≈ 9353.1 m2).The maximum area is a regular hexagon with sides 60 m which has an area of:area_regular_hexagon = 1/2 x 3 x √3 x side2= 1/2 x 3 x √3 x (60 m)2vv= 5400√3m2≈ 9353.1 m2
For a Reuleaux triangle: Area = 1/2(π - √3)diameter2 = 1/2(π - √3)112 ≈ 85.28m2
Entire surface area: (2*pi*0.752)+(pi*1.5*5) = 27.096 square m to 3 decimal places
As an area can be any shape, there is no formula for finding length and breadth when given area.But if you have a rectangle:Area = length × breadthWhich can be rearranged to give:Breadth = Area ÷ LengthorLength = Area ÷ BreadthThere is no one solution for this - pick any breadth (or length) and you can work out the length (or breadth) of the rectangle so that it has the given area.For example, If a rectangle has an area of 12 m² it could have dimensions:breadth = 1 m → length = 12 m² ÷ 1 m = 12 mbreadth = 2 m → length = 12 m² ÷ 2 m = 6 mbreadth = 3 m → length = 12 m² ÷ 3 m = 4 mAll those rectangles: 1m by 12 m, 2 m by 6 m, 3 m by 4m have an area of 12 m²The lengths need not be whole numbers, giving further rectangles, for example:breadth = 0.5 m → length = 12 m² ÷ 0.5 m = 24 mbreadth = 1.5 m → length = 12 m² ÷ 1.5 m = 8 mbreadth = 2.5 m → length = 4.8 m