Area of a possible rectangle: 9 times 2 = 18 square m
A=m*h m=(a+b)/2
Area = pi*82 = 201.062 square m and rounded to 3 dp
area of rectangle = l * b area = 8 * 5 =40 m ^2 ( 1 m=100 cm 500cm= 5 m)
C = 2πr = 100 mr = 100/(2π) = 50/πA = πr^2 = π(50/π)^2 = 2500/π m^3 ≈ 795.775 m^3
the area of an mxm square is m^2. For example, a 3x3 square has area 3^2 or 9
Area of a triangle = 1/2 * base * height = 1/2*3*5 = 7.5 square metres.
The Surface area is given by 2(lb+bh+hl) in this case, l=5m b=3m h=2m therefore the Surface area, sa=2(5*3+3*2+2*5) =2(15+6+10) =2(31) sa =62m2
Area of a cirlce = pi*r^2. A = pi*3^2 = 9*pi = 28.2743 m^2.
( m^2 - m - 3 ) + ( m - 4 ) = m^2 - m - 3 + m - 4 = m^2 - 7Answer: m^2 - 7
Area of a rectangle = length of base x height Area of a triangle = (length of base x height)/2 A.............................................. B mmmmmmmmmmmmmmmmmmm m.............................................. m m ..............................................m m.............................................. m m.............................................. m m.............................................. m m ..............................................m m.............................................. m mmmmmmmmmmmmmmmmmmm C ..............................................D Area of ABCD = AB x AC Area of ABCD = (AB X AC)/2 Then Area of ABCD = 2 Area of ABC
If all the vertices of the regular hexagon are joined to the centre of the hexagon, 6 equilateral triangles are created: the area of the hexagon is 6 times the area of one of these triangles. If the length of the side of the hexagon is m, then the length of each of the sides of these triangles is also m. Using Pythagoras the height of these triangles can be found to be m x sqrt(3)/2. Thus the area of the hexagon = 6 x area triangle = 6 x (m x m x sqrt(3)/2) / 2 = (3/2) sqrt(3) m2 ~= 2.6 x square of length_of_side
If they have the same radius then it is: 3 to 2
A hexagon with sides of 60 m will have an area greater than 0 m2 and less than or equal to 5400√3 m2 (≈ 9353.1 m2).The maximum area is a regular hexagon with sides 60 m which has an area of:area_regular_hexagon = 1/2 x 3 x √3 x side2= 1/2 x 3 x √3 x (60 m)2vv= 5400√3m2≈ 9353.1 m2
For a Reuleaux triangle: Area = 1/2(π - √3)diameter2 = 1/2(π - √3)112 ≈ 85.28m2
Entire surface area: (2*pi*0.752)+(pi*1.5*5) = 27.096 square m to 3 decimal places
Assuming you mean the total surface area of the cuboid with measurements 5m x 3m x 2m:There are 6 faces, the opposite pairs of which are the same size, making 3 different face sizes; so double the area of the three different faces:Surface_area = 2 x (5 m x 3 m + 5 m x 2 m + 3 m x 2 m)= 2 x (15 m2 + 10 m2 + 6 m2)= 62 m2