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Prove that the perpendicular at the point of contact to the tangent to a circle passes through the center?
Draw a circle with centre O. draw a tangent PR touching circle at P. Draw QP perpendicular to RP at point P, Qp lies in the circle. Now, angle OPR = 90 degree (radius perpendicular to tangent) also angle QPR = 90 degree (given) Therefore angle OPR = angle QPR. This is possible only when O lies on QP. Hence, it is prooved that the perpendicular at the point of contact to the tangent to a circle passes through the centre. Answer By- Rajendra Meena, Jaipur, India. email: rajendra.meena21@gmail.com
How sine is the y coordinate of a unit circle?
Sine is NOT the y coordinate: it is the sine of the angle made by the x-axis and the radius from a point on the circle. It is the cosine of the angle made with the y-axis.Consider any point, P, on the unit circle with coordinates (x, y). And let Q be the foot of the perpendicular from P to the x-axis. Then y = PQ.Now, in the right angled triangle OPQ, if OP makes an angle theta with the x axis, then sin(theta) = PQ/OP = y/OP and since OP is the radius of a unit circle, OP = 1 so that sin(theta) = y.
An angle of 50 degrees in standard position has its terminal side in the first quadrant. What are the coordinates of point P on the unit circle?
Draw a picture of this you will see that you can form a triangle with the radius of the circle being 1. This is the hypotenus of the triangle Using trig, x = cos 50 y = sin 50 P is (x,y) = P is (cos 50,sin 50) = (0.643, 0.766)
In circle P XY 2.4 cm. What is the circumference of the circle?
It is 7.5 cm.
If angle P is three less than twice the measure angle Q angle P and angle Q are supplementary angles what are their measurements?
Assuming the angles are expressed in degrees: P = 2Q -3° (because "angle P is three less than twice the measure angle Q") P + Q = 180° (because they are supplementary angles) P+Q = 2Q - 3° + Q = 3Q -3° = 180° 3Q = 183° Q = 61° P = 2∙61° -3° = 122° - 3° = 119° If the angles are expressed in radians, the math is similar except you start with P = 2Q - 3 and P+Q = π yielding P = 2π/3 -1 and Q = π/3 +1
In circle p what is the measure of ABC?
To determine the measure of angle ABC in circle P, we need additional information, such as the positions of points A, B, and C or any relevant measurements or relationships (like whether they are inscribed angles, central angles, etc.). Without that context, it is impossible to provide a specific measure for angle ABC. If you have more details, please provide them for a more accurate answer.
Mateo is constructing an equilateral triangle inscribed in a circle with center P. What is his first step?
Mateo's first step in constructing an equilateral triangle inscribed in a circle with center P is to draw the circle itself, ensuring that the radius is defined. Next, he can mark a point on the circumference of the circle to serve as one vertex of the triangle. From there, he will need to use a compass to find the other two vertices by measuring the same distance (the length of the triangle's side) along the circumference of the circle. Finally, he will connect the three points to form the equilateral triangle.
Percentage sections in a circle graph?
A one-percent sector subtends an angle of 3.6 degrees at the centre.
What is the measure of angle BPC in the circle?
The answer will depend on the location of the points B, P and C.
Angle P is a right angle What is the measure of angle P?
The measure of angle P is 90 degrees.
Prove that the perpendicular at the point of contact to the tangent to a circle passes through the center?
Draw a circle with centre O. draw a tangent PR touching circle at P. Draw QP perpendicular to RP at point P, Qp lies in the circle. Now, angle OPR = 90 degree (radius perpendicular to tangent) also angle QPR = 90 degree (given) Therefore angle OPR = angle QPR. This is possible only when O lies on QP. Hence, it is prooved that the perpendicular at the point of contact to the tangent to a circle passes through the centre. Answer By- Rajendra Meena, Jaipur, India. email: rajendra.meena21@gmail.com
What is the formula for calculating the arc length?
For a circle: Arc Length= R*((2*P*A)/(360)) R being radius, P being pi (3.14159), and A being the measure of the central angle.
If the perimeter of a square is 36 what is the circumference of a circle?
If you mean a circle inscribed in the square: C = circumference, π = pi, r = radius, s = side, P = perimeter C = 2πr r = s/2 C = πs s = P/4 C = πP/4 So for this problem, the circumference is 9π, or about 28.3 If you mean a square inscribed in the circle, the computations are practically the same, except: r = sqrt(2)s/2 C = sqrt(2)πs C = sqrt(2)πP/4 So for this problem, the circumference is sqrt(2)9π, or about 40.0
What is the P-P-P bond angle in white phosphorus?
The P-P-P bond angle in white phosphorus is approximately 60 degrees.
How sine is the y coordinate of a unit circle?
Sine is NOT the y coordinate: it is the sine of the angle made by the x-axis and the radius from a point on the circle. It is the cosine of the angle made with the y-axis.Consider any point, P, on the unit circle with coordinates (x, y). And let Q be the foot of the perpendicular from P to the x-axis. Then y = PQ.Now, in the right angled triangle OPQ, if OP makes an angle theta with the x axis, then sin(theta) = PQ/OP = y/OP and since OP is the radius of a unit circle, OP = 1 so that sin(theta) = y.
How do you find degrees on a circumfince?
I presume you mean the circumference of a circle. If P and Q are two points on the circumference of a circle with center O, the number of degrees in the arc PQ is defined as the number of degrees in the angle POQ.
PF3Cl2 is a nonpolar molecule What is the f-p-f bond angle cl-p-cl angle bond and the f-p-cl angle bond?
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
