The answer will depend on the location of the points B, P and C.
angle P
The complement of an angle can be added to that angle to get a total of 90 degrees. Therefore, if your angle was 45*, set up a simple algebra problem. 45+x=90 subtract 45, you get x=45 The complement of a 45* angle is 45*. The complement of a 30* angle is 60, etc. The supplement of an angle can be added to said angle to get a total of 180 degrees, so if your angle is 45*, set up an algebra problem (again :P). 45+x=180 subtract 45, x=135. The supplement of a 45* angle is 135*. The supplement of a 30*angle is 150*, etc. Hope this helped!
l M l l Q____l____ N lO l l l P Let MP & NQ be lines intersecting at O. Then angle MON + angle NOP = 180 degrees (linear pair) Angle MOQ + angle QOP = 180 degrees (linear pair) Adding the equations, Angle MON + Angle NOP + Angle MOQ + Angle QOP = 180 + 180 degrees = 360 degrees. Therefore all angles around O sum upto 360 degrees.
Definition of angle bisector:An angle is formed by two rays with a common endpoint. The angle bisector is a ray or line segment that bisects the angle, creating two congruent angles. To construct an angle bisector you need a compass and straightedge.Definition of midpoint:Midpoint of a line segment is the point that is halfway between the endpoints of the line segment. A line segment has only one midpoint. If AB is a line segment and P is the midpoint, then AP = BP =
Angle q will be less than 90 degrees because a right angle is 90 degrees and the 3 angles in a triangle add up to 180 degrees.
By using trigonometry or using Pythagoras' theorem for a right angle triangle.
55 - 20 = 35
<p><p> 180-x=3(90-x)-60 180-x=270-3x-60 3x-x=270-180-60 2x=30 x=15
if you read this you smell :p
130 Degrees180-24=156So you know that the sum of all the angles is 180, so the sum of the other two angles is 156. You Know that angle p is equal to some number x. And you know the angle n is five times some number x or 5x. You know the sum of the two angles numerically and algebraically.6x=156x=26n=5xn=5(26)n=130
Electrical angle is half of mechanical angle in unipolar electrical machines. In multipolar electrical machines, the relationship between the mechanical angle and electrical angle is Electrical angle = (P/2) x Mechanical angle where: P = Number of poles.
Assuming the angles are expressed in degrees: P = 2Q -3° (because "angle P is three less than twice the measure angle Q") P + Q = 180° (because they are supplementary angles) P+Q = 2Q - 3° + Q = 3Q -3° = 180° 3Q = 183° Q = 61° P = 2∙61° -3° = 122° - 3° = 119° If the angles are expressed in radians, the math is similar except you start with P = 2Q - 3 and P+Q = π yielding P = 2π/3 -1 and Q = π/3 +1
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
Sum of all three angles is 180 degrees. p = 36 so q+r = 180-36 = 144 degrees. Now, q = 5r so 144 = q+r = 5r+r = 6r so r = 144/6 = 24 and then q = 5r = 5*24=120 Answer: q = 120 deg, r = 24 deg
The P-P-P bond angle in white phosphorus is approximately 60 degrees.
The answer will depend on the location of the points B, P and C.