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Q: Name the points that are a distance of 5 units from D?
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Related questions

What is the distance between the points (-5 -2) and (3 13)?

Points: (-5, -2) and (3, 13)Distance works out as 17 units


What is the distance between the following points. (1 -2) and (1 -5)?

Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula


What is the distance between points (-6 1) and (-2 -2)?

Points: (-6, 1) and (-2, -2) Distance: 5 units


What is the distance between points (-5 -3) and (7 7)?

If you mean points of (-5, -3) and (7, 7) then by using the distance formula it is 120 units


What is the taxi distance between the points 0-0 and 5-2?

Using Pythagoras: 5 squared + 2 squared = √21 which is about 4.58.


What is the distance between the points (4 5) and (10 13) on a coordinate plane?

10 units


What is the approximate distance between the points (-5 1) and (-2 3) on a coordinate grid?

3.61 units


What is the distance between the points (5 7) and (-3 4) on the coordinate plane?

A. 8.54 units B. 7.28 units C. 3.61 units D. 12.04 units


What is the distance between the points (-7 -13) and (8 -5)?

To find the distance between two points (x0, y0) and (x1, y1) use Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((8 - -7)² + (-5 - -13)²) → distance = √(15² + 8²) → distance = √289 → distance = 17 units.


What is the distance between (-24) and (54) on a coordinate grid?

If you mean points of (-2, 4) and (5, 4) then using the distance formula it is 7


The run is the change between two points along a line?

The run, combined with the rise (the distance in units up) creates the slope of a line. In the slope 5/3 , 5 is the rise and 3 is the run, meaning that to find the next point on the line you would first move up five units, then go to the right 3 units.


What is the approximate distance between the points 1 -2 and -9 3 on a coordinate grid?

The distance is the square root of 125 (which is about 11.18) 1 to -9 = 10 units -2 to 3 = 5 units distance = sqrt (102 + 52) = sqrt (125)