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Find the distance between the points -2 2 and -2 2?
0 0
What is the distance between the points -2 0 and -1 -1?
Answer: 1
What is the distance between the two points 2 3 and 0 -2?
The square root of (2x2)+(5x5) is 5.385164807134504 ' . . . . . . .
What is the distance between the points -2 0 and 5 3?
Let (x1, y1) = (-2, 0) and (x2, y2) = (5, 3). Distance between two points = square root of [(x2 - x1)2 + (y2 - y1)2] = square root of [(5 - -2)2 + (3 - 0)2] = square root of (72 + 32) = square root of 58
What is the distance between this pair of points 0 4 and -4 6?
Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============
Find the distance between the points -2 2 and -2 2?
0 0
What is the distance between points A 2 3 2 and B 0 0 0?
7
What is the distance between the points 2 and 4 and 5 and 0?
-2 & 5
What is the distance between the points -2 0 and -1 -1?
Answer: 1
What is the distance between the points -2 2 and -2 2?
0 is the answer. If you start at -2 2, and end at -2 2, you moved 0 spots so there is no distance.
What is the distance between points (23) and (70) to the nearest tenth?
The distance between the points of (2, 3) and (7, 0) is the square root of 34
What is the distance between these two points 0 0 and 8 2?
Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246
What is the distance between points (0 0) and (-2 -2)?
It works out as the square root of 8 which is about 2.828 rounded to 3 decimal places
What is the distance between the two points 2 3 and 0 -2?
The square root of (2x2)+(5x5) is 5.385164807134504 ' . . . . . . .
What is the taxi distance between the points 0-0 and 5-2?
Using Pythagoras: 5 squared + 2 squared = √21 which is about 4.58.
Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the distance between points 0 4 and -4 6?
(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============
