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If you mean points of (-5, 1) and (-2, 3) then using the distance formula it is the square root of 13 or about 3.61 rounded to 2 decimal places
Points: (2, 4) and (5, 0) Distance: 5
If you mean points of (-5, 1) and (-2, 3) then using the distance formula it is the square root of 13 or about 3.6
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You can use Pythagoras to solve this to get the co-ordinates. from Pythagoras we have a^2 + b^2 = c^2 For this a and b will be the x and y distance and c the distance between the 2 points so we get (7-2) ^2 + (8-y1)^2 = 13^2 So we need so solve this to get a correct solution which is (8-y1)^2 = 144 so 8 - y1 = + or - 12 so y1 = -4 or y1 = 20