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If triangle PQR is congruent to triangle STU which statement must be true?
PQ ST
How do you prove rhs congruence?
Here is the answer to your query. Consider two ∆ABC and ∆PQR. In these two triangles ∠B = ∠Q = 90�, AB = PQ and AC = PR. We can prove the R.H.S congruence rule i.e. to prove ∆ABC ≅ ∆PQR We need the help of SSS congruence rule. We have AB = PQ, and AC = PR So, to prove ∆ABC ≅ ∆PQR in SSS congruence rule we just need to show BC = QR Now, using Pythagoras theorems in ∆ABC and ∆PQR Now, in ∆ABC and ∆PQR AB = PQ, BC = QR, AC = PR ∴ ∆ABC ≅ ∆PQR [Using SSS congruence rule] So, we have AB = PQ, AC = PR, ∠B = ∠Q = 90� and we have proved ∆ABC ≅ ∆PQR. This is proof of R.H.S. congruence rule. Hope! This will help you. Cheers!!!
The perimeters of two similar triangles abc and pqr are 36 cm and 24 cm respectively if pq equals 10 cm find ab?
Since 36=24+1/2.24 and abc and pqr are similar, ab= 10+1/2.10=15.
Which expression gives the length of PQ in the triangle shown below?
A triangle has 3 line segments
If pq and rs intersect to from four right angles what is true?
Is PQ |_ RS
