Sorry, but data not adequate. However, I'll try. Suppose the triangle is right angled at R. Then PQ = hypotenuse = 8. Further, if the triangle is isosceles, then RQ = 4 times sqrt(2).
PQ ST
Here is the answer to your query. Consider two ∆ABC and ∆PQR. In these two triangles ∠B = ∠Q = 90�, AB = PQ and AC = PR. We can prove the R.H.S congruence rule i.e. to prove ∆ABC ≅ ∆PQR We need the help of SSS congruence rule. We have AB = PQ, and AC = PR So, to prove ∆ABC ≅ ∆PQR in SSS congruence rule we just need to show BC = QR Now, using Pythagoras theorems in ∆ABC and ∆PQR Now, in ∆ABC and ∆PQR AB = PQ, BC = QR, AC = PR ∴ ∆ABC ≅ ∆PQR [Using SSS congruence rule] So, we have AB = PQ, AC = PR, ∠B = ∠Q = 90� and we have proved ∆ABC ≅ ∆PQR. This is proof of R.H.S. congruence rule. Hope! This will help you. Cheers!!!
Since 36=24+1/2.24 and abc and pqr are similar, ab= 10+1/2.10=15.
A triangle has 3 line segments
Is PQ |_ RS
PQ ST
m = pqr/s Multiply both sides by s: ms = pqr Divide both sides by pq: ms/pq = r
In triangle PQR, the sides are typically denoted as follows: side PQ is opposite vertex R, side QR is opposite vertex P, and side RP is opposite vertex Q. The lengths of these sides can vary depending on the specific dimensions of the triangle. If you have particular measurements or properties in mind for triangle PQR, please provide them for a more detailed response.
The scale factor of the dilation that transforms triangle PQR to triangle P'Q'R' can be determined by comparing the lengths of corresponding sides of the triangles. If, for example, the length of side PQ is 4 units and the length of side P'Q' is 8 units, the scale factor would be 8/4 = 2. This means that triangle P'Q' is twice the size of triangle PQR, indicating a dilation with a scale factor of 2.
To determine the scale factor from triangle PQR to triangle STU, you need the lengths of corresponding sides from both triangles. The scale factor is found by dividing the length of a side in triangle STU by the length of the corresponding side in triangle PQR. For example, if side PQ measures 4 units and side ST measures 8 units, the scale factor would be 8/4 = 2. Without specific side lengths, the scale factor cannot be calculated.
Here is the answer to your query. Consider two ∆ABC and ∆PQR. In these two triangles ∠B = ∠Q = 90�, AB = PQ and AC = PR. We can prove the R.H.S congruence rule i.e. to prove ∆ABC ≅ ∆PQR We need the help of SSS congruence rule. We have AB = PQ, and AC = PR So, to prove ∆ABC ≅ ∆PQR in SSS congruence rule we just need to show BC = QR Now, using Pythagoras theorems in ∆ABC and ∆PQR Now, in ∆ABC and ∆PQR AB = PQ, BC = QR, AC = PR ∴ ∆ABC ≅ ∆PQR [Using SSS congruence rule] So, we have AB = PQ, AC = PR, ∠B = ∠Q = 90� and we have proved ∆ABC ≅ ∆PQR. This is proof of R.H.S. congruence rule. Hope! This will help you. Cheers!!!
Since 36=24+1/2.24 and abc and pqr are similar, ab= 10+1/2.10=15.
Since the sides of triangle are equal, the triangles are equilateral. Just for your information, in this question, we do not require the length of sides. It is just additional information. :) The area of equilateral triangle is: (√3)/4 × a², where a is the side of the equilateral triangle. For triangle ABC, area will be = (√3)/4 × a² (Let 'a' is the side of triangle ABC) Since, side of triangle PQR is half that of ABC, it will be = a/2 Therefore, area of triangle PQR = (√3)/4 × (a/2)² = (√3)/16 × a² Take the ratio of areas of triangle ABC and PQR: [(√3)/4 × a²] / [(√3)/16 × a²] = 4:1
Suppose the circle meets QR at A, RP at B and PQ at C. PQ = PR (given) so PC + CQ = PB + BR. But PC and PB are tangents to the circle from point P, so PC = PB. Therefore CQ = BR Now CQ and AQ are tangents to the circle from point Q, so CQ = AQ and BR and AR are tangents to the circle from point R, so BR = AR Therefore AQ = AR, that is, A is the midpoint of QR.
To show that triangle ABC is congruent to triangle PQR by the SSS (Side-Side-Side) postulate, all three corresponding sides must be congruent. This means that side AB must equal side PQ, side BC must equal side QR, and side CA must equal side RP. If all corresponding sides are confirmed to be equal in length, then the triangles are congruent by SSS.
To determine ( \frac{PQ}{RS} ), you need the values of ( PQ ) and ( RS ). Once you have those values, you simply divide ( PQ ) by ( RS ). If ( PQ ) equals 10 and ( RS ) equals 5, for example, then ( \frac{PQ}{RS} = \frac{10}{5} = 2 ). Please provide the specific values for a precise answer.
A triangle has 3 line segments