8 and 6
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
Length of rectangle: 7.9 cm Width of rectangle: 1.3 cm Area of rectangle: 7.9 times 1.3 = 10.27 square cm
let width= x length= 8ft+x area of rectangle= 345 area= l*b = 8+x*x=345 = 2x= 337 x=168.5 Length=176.5 Breadth=168.5 SORRY THE ANS IS WRONG.
9 inches
if the width is 3.5 then the length is 10 10 = 3 +2(3.5) 10 x 3.5 = 35
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
Length of rectangle: 7.9 cm Width of rectangle: 1.3 cm Area of rectangle: 7.9 times 1.3 = 10.27 square cm
Its length is 1+ square root of 66 ft and its width is -1+ square root of 66 ft
let width= x length= 8ft+x area of rectangle= 345 area= l*b = 8+x*x=345 = 2x= 337 x=168.5 Length=176.5 Breadth=168.5 SORRY THE ANS IS WRONG.
They are: 3 inches and 5 inches respectively
10x2
9 inches
the width is always shorter than the length. other than that, you would require more information about the rectangle (such as the area or the diagonal measurement) to ascertain the width
Badly expressed! Do you mean "what is the area of a rectangle with a length that is 3 more than twice its width?" ? If you have a width, then presumably you have a length, in which case you presumably have a rectangle. But what do we want to know about this rectangle? You haven't said. Its area? Its perimeter? Its color? Its shoe size?
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
4 x 13 = 52cm2 Length x Width = Area