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There are three plane figures and cube, which is three dimensional.
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Square Triangle Pentagon Hexagon Cube Octagon?
The odd one out is the cube which is a 3D shape whereas the rest are 2D shapes if that is your question.
What is the odd word out of cube triangle trapezium square?
It is a cube which is 3D whereas the rest are 2D.
What is the only odd single-digit number greater than 1 whose cube is a perfect square?
7 * * * * * What? 73 = 343 which is the square of 18.52... hardly a perfect square! The correct answer is 9.
Which is the odd one out circle square rectangle?
rectangle
A shape with 7 silds is called a?
7,5,3 is impossible, because an odd shape, meeting two others, forces the others to be equal. Here is a generalization of that rule. Let each corner have the pattern x,y,z,y where all three variables are different and y is odd. Walk around y back to start and arrive at a contradiction. The same is true of x,y,z,z and x,y,y,x and x,y,y,z. Thus 6,3,3,4 is impossible, even though the angles sum to less than 360°. When building semiregular solids, we don't have to worry about anything beyond the octagon. Here's why. Let x be a 9-gon or higher, hence it consumes 140° or more. Note that x cannot join four other shapes at a vertex, and if it joins three other shapes, two of them must be triangles. If the third is a triangle we have the anti-gonal prism. If the third is a square, x,3,4,3 and x,4,3,3 both fail the walkaround test. If the third is a pentagon the angles exceed 360°. Thus x meets two other shapes. If one is a triangle the other must be x, which is valid for x < 12. Yet if x is odd, and greater than 3, it fails the walk around test. Therefore the semiregular solid x,3,x is valid for x = 3, 4, 6, 8, 10. That takes care of x meeting a triangle. Without a triangle, x meets squares or higher. If x meets two squares we have the gonal prism. The shape x,4,5 fails the walkaround test, and x,4,6 fails the walk around test when x = 9 or 11. The pattern x,4,6 is valid when x = 10, another use for the decagon. These shapes consume too much angle when x is 12 or higher. Finally, x,5,5 fails the walk around test, and x,5,6 is too big. Hereinafter, we can restrict attention to octagons and below. If the octagon meets three other shapes, two of them are triangles. Let the third be a square, to avoid the anti-gonal prism. Yet 8,3,4,3 and 8,3,3,4 fail the walkaround test, so the octagon meets two other shapes. If one of them is odd then the other is an octagon, and that only leaves room for a triangle. This is 8,8,3, the truncated cube. If the octagon meets two even shapes, one of them is a square. To avoid the gonal prism, the other is a hexagon. This is another valid shape. That takes care of the octagon. If a heptagon, 7 sides, meets three shapes, two of them are triangles. The third creates the anti-gonal prism, or fails the walkaround test, hence the heptagon meets two other shapes. Since 7 is odd, these shapes are equal. They must be even, else we fail the walkaround test. Skip the squares (gonal prism) and move to hexagons, but that introduces too much angle. If a pentagon meets two other shapes they too are pentagons, or they are copies of an even shape, a square (gonal prism) or a hexagon (soccer ball). If the pentagon meets four other shapes they are triangles, and that is valid. If the pentagon meets three other shapes, at least one is a triangle. If the second is a triangle, the third should not be a triangle, else we have an anti-gonal prism. Note that 5,3,3,4 5,3,4,3 5,3,3,5 5,3,3,6 5,3,6,3 all fail the walkaround test. That leaves 5,3,5,3, which is valid. If the third shape is a square then so is the fourth. Since 5,3,4,4 fails, we are left with 5,4,3,4, which is valid. That's it for the pentagon. Join two hexagons with a triangle or a square; both are valid. Hereinafter there is at most one hexagon; everything else being squares or triangles. If a hexagon meets two shapes, one cannot be a triangle, so we're talking about two squares, the gonal prism. If the hexagon meets 3 other shapes, the first two are triangles. Make the third a square, avoiding the anti-gonal prism. Yet 6,3,3,4 and 6,3,4,3 both fail the walkaround test. That's it for the hexagon. Three squares and a triangle - that works. Two squares and two triangles makes the shape 4,3,4,3. One square joins 4 triangles to make a snub solid. That's all the semiregular solids. They are presented in the table below. {| ! Name ! Pattern ! Vertices ! Edges ! Faces | Gonal Prism n,4,4 2n 3n n+2 Anti-gonal Prism n,3,3,3 2n 4n 2n+2 Tetrahedron 3,3,3 4 6 4 Cube 4,4,4 8 12 6 Octahedron 3,3,3,3 6 12 8 Dodecahedron 5,5,5 20 30 12 Icosahedron 3,3,3,3,3 12 30 20 Truncated Tetrahedron 6,6,3 12 18 8 Truncated Cube 8,8,3 24 36 14 Truncated Octahedron 6,6,4 24 36 14 Truncated Dodecahedron 10,10,3 60 90 32 Truncated Icosahedron 6,6,5 60 90 32 Cuboctahedron 4,3,4,3 12 24 14 Icosidodecahedron 5,3,5,3 30 60 32 Truncated Cuboctahedron 8,6,4 48 72 26 Truncated Icosidodecahedron 10,6,4 120 180 62 Rhombic Cuboctahedron 4,4,4,3 24 48 26 Rhombic Icosidodecahedron 5,4,3,4 60 120 62 Snub Cuboctahedron 4,3,3,3,3 24 60 38 Snub Icosidodecahedron 5,3,3,3,3 60 150 92 |} 7,5,3 is impossible, because an odd shape, meeting two others, forces the others to be equal. Here is a generalization of that rule. Let each corner have the pattern x,y,z,y where all three variables are different and y is odd. Walk around y back to start and arrive at a contradiction. The same is true of x,y,z,z and x,y,y,x and x,y,y,z. Thus 6,3,3,4 is impossible, even though the angles sum to less than 360°. When building semiregular solids, we don't have to worry about anything beyond the octagon. Here's why. Let x be a 9-gon or higher, hence it consumes 140° or more. Note that x cannot join four other shapes at a vertex, and if it joins three other shapes, two of them must be triangles. If the third is a triangle we have the anti-gonal prism. If the third is a square, x,3,4,3 and x,4,3,3 both fail the walkaround test. If the third is a pentagon the angles exceed 360°. Thus x meets two other shapes. If one is a triangle the other must be x, which is valid for x < 12. Yet if x is odd, and greater than 3, it fails the walk around test. Therefore the semiregular solid x,3,x is valid for x = 3, 4, 6, 8, 10. That takes care of x meeting a triangle. Without a triangle, x meets squares or higher. If x meets two squares we have the gonal prism. The shape x,4,5 fails the walkaround test, and x,4,6 fails the walk around test when x = 9 or 11. The pattern x,4,6 is valid when x = 10, another use for the decagon. These shapes consume too much angle when x is 12 or higher. Finally, x,5,5 fails the walk around test, and x,5,6 is too big. Hereinafter, we can restrict attention to octagons and below. If the octagon meets three other shapes, two of them are triangles. Let the third be a square, to avoid the anti-gonal prism. Yet 8,3,4,3 and 8,3,3,4 fail the walkaround test, so the octagon meets two other shapes. If one of them is odd then the other is an octagon, and that only leaves room for a triangle. This is 8,8,3, the truncated cube. If the octagon meets two even shapes, one of them is a square. To avoid the gonal prism, the other is a hexagon. This is another valid shape. That takes care of the octagon. If a heptagon, 7 sides, meets three shapes, two of them are triangles. The third creates the anti-gonal prism, or fails the walkaround test, hence the heptagon meets two other shapes. Since 7 is odd, these shapes are equal. They must be even, else we fail the walkaround test. Skip the squares (gonal prism) and move to hexagons, but that introduces too much angle. If a pentagon meets two other shapes they too are pentagons, or they are copies of an even shape, a square (gonal prism) or a hexagon (soccer ball). If the pentagon meets four other shapes they are triangles, and that is valid. If the pentagon meets three other shapes, at least one is a triangle. If the second is a triangle, the third should not be a triangle, else we have an anti-gonal prism. Note that 5,3,3,4 5,3,4,3 5,3,3,5 5,3,3,6 5,3,6,3 all fail the walkaround test. That leaves 5,3,5,3, which is valid. If the third shape is a square then so is the fourth. Since 5,3,4,4 fails, we are left with 5,4,3,4, which is valid. That's it for the pentagon. Join two hexagons with a triangle or a square; both are valid. Hereinafter there is at most one hexagon; everything else being squares or triangles. If a hexagon meets two shapes, one cannot be a triangle, so we're talking about two squares, the gonal prism. If the hexagon meets 3 other shapes, the first two are triangles. Make the third a square, avoiding the anti-gonal prism. Yet 6,3,3,4 and 6,3,4,3 both fail the walkaround test. That's it for the hexagon. Three squares and a triangle - that works. Two squares and two triangles makes the shape 4,3,4,3. One square joins 4 triangles to make a snub solid. That's all the semiregular solids. They are presented in the table below. {| ! Name ! Pattern ! Vertices ! Edges ! Faces | Gonal Prism n,4,4 2n 3n n+2 Anti-gonal Prism n,3,3,3 2n 4n 2n+2 Tetrahedron 3,3,3 4 6 4 Cube 4,4,4 8 12 6 Octahedron 3,3,3,3 6 12 8 Dodecahedron 5,5,5 20 30 12 Icosahedron 3,3,3,3,3 12 30 20 Truncated Tetrahedron 6,6,3 12 18 8 Truncated Cube 8,8,3 24 36 14 Truncated Octahedron 6,6,4 24 36 14 Truncated Dodecahedron 10,10,3 60 90 32 Truncated Icosahedron 6,6,5 60 90 32 Cuboctahedron 4,3,4,3 12 24 14 Icosidodecahedron 5,3,5,3 30 60 32 Truncated Cuboctahedron 8,6,4 48 72 26 Truncated Icosidodecahedron 10,6,4 120 180 62 Rhombic Cuboctahedron 4,4,4,3 24 48 26 Rhombic Icosidodecahedron 5,4,3,4 60 120 62 Snub Cuboctahedron 4,3,3,3,3 24 60 38 Snub Icosidodecahedron 5,3,3,3,3 60 150 92 |}
Square Triangle Pentagon Hexagon Cube Octagon?
The odd one out is the cube which is a 3D shape whereas the rest are 2D shapes if that is your question.
What is the odd word out of cube triangle trapezium square?
It is a cube which is 3D whereas the rest are 2D.
Which is the odd one in the following heptagon triangle hexagon cube?
Which is the odd one in the following heptagon triangle hexagon cube?Read more: Which_is_the_odd_one_in_the_following_heptagon_triangle_hexagon_cube
Which would be the odd one out if there was a tetrahedron a square pyramid or a triangle?
triangle - it is planar
How many odd numbers are odd on a number cube?
There are five odd numbers on an odd number cube?
What is the odd cube number of 1728?
1728 is even so it cannot have an odd cube root.
What do odd triangles have to do with squares and cubes?
Well if you half any quadrilateral it comes up with a triangle and a square is a quadrilateral.
How are the odd numbers arranged in Pascal's Triangle?
how are the odd numbers arranged Pascal's Triangle?
What are geometric words beginning with O?
obliqueorder of operationsoperandobtuseoctalObtuse, oblong, oblique· obtuse· octagon· odd· one· ovalObtuse, odd number, oval, octagon and one are math terms that begin with the letter o.
What is the cube of an odd number?
the cube of 1 is 1 as is any operation done against 1 3x3x3= 27 so 27 is the cube of the odd number 3
What is the odd number out 16 36 64 27 81?
The only number in that list which is not a square number is 27. 27 is a cube number.
What is an Odd square?
It is the square of an odd integer.
