The question does not specify the starting point.
Suppose the specified line has gradient m. Also suppose the specified distance is d.Then x = sqrt[d2/(1 + m2)] and y = m*x.A translation, by a distance x in the horizontal direction and y=mx in the vertical direction will move the point by the specified distance in the direction of the specified line.
the answeri 20cm
Suppose the polygon's vertices are denoted A1A2...An. We can fix one endpoint of the diagonal at A1 and count the number of ways to choose from the remaining vertices. There are n-3 vertices to choose from, because we cannot count A1, nor count A2 or An (since they are directly next to A1). There are n vertices total, so we multiply to get n(n-3). However, we have to divide by 2 because we count each diagonal twice. The diagonal AiAj is the same as AjAi, and each is counted. Therefore, the number of diagonals in an n-gon is n(n-3)/2.
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60 degrees.
Error is 0.05/2.00 expressed as a percentage = 0.05/2.00 x 100 = plus or minus 2.5%
I suppose it would depend on which side of the planet you are on. If it's clockwise on one side then it's counterclockwise on the opposite side.
I suppose they could be called a pair, just like two horizontal lines could be called a pair, but it's not a "mathematical" or "technical" term.
A) Rotate 360 degrees counterclockwise, then shift 1 unit up. B) Rotate 180 degrees counterclockwise, then shift 1 unit down. C)Rotate 90 degrees counterclockwise, then shift 1 unit up. D) Rotate 270 degrees counterclockwise, then shift 1 unit down.
All the planets orbit counterclockwise around the Sun.
A trajectory is the angle made with the horizontal when a projectile is fired. Suppose the projectile is a cannon ball. Assuming air is frictionless, that cannon ball will travel the greatest distance if the trajectory is 45 degrees from horizontal.
Contact the company it could be a faulty test.
11100101
Does... not... compute... Too many missing variables, or just a poorly written question.
Yes and on you're as dominant wrist for positive energy!
Now why do you suppose we say "over" in that description ? Could it be because the fraction has the '5' written 'over' the '12', with a horizontal bar between them ?
Numbers have no effect on marriage. From the lighter side . . . I suppose it would be considered a positive effect if a woman was richly widowed twelve times!