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Suppose the polygon's vertices are denoted A1A2...An. We can fix one endpoint of the diagonal at A1 and count the number of ways to choose from the remaining vertices. There are n-3 vertices to choose from, because we cannot count A1, nor count A2 or An (since they are directly next to A1).

There are n vertices total, so we multiply to get n(n-3). However, we have to divide by 2 because we count each diagonal twice. The diagonal AiAj is the same as AjAi, and each is counted. Therefore, the number of diagonals in an n-gon is n(n-3)/2.

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Q: What is the formula to find the number of diagonals in a polygon?
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How yo find the formula on how to solve the number of diagonals in a polygon?

It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon


How can you find the number of diagonals in a polygon?

The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon


How many diagonals does a 11 sided polygon have?

You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.


What is the formula to find diagonals in polygon?

0.5*(n2-3n) where n is equal to the number of sides of the polygon


How do you find the number of diagonals in a polygon?

Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon


What rule can be used to find number of diagonals that can be drawn from one vertex of regular polygon?

You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.


How many diagonals does a 30 sided polygon have?

The formula used to find the number of diagonals in a polygon is n(n-3)/2. 30 x 27/2 = 810/2 = 405 diagonals.


How do you find the number of sides of a polygon given the number of diagonals?

Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.


How do you find the diagonals in a pentagon?

Use the formula: 0.5*(n2-3n) whereas 'n' is the number of sides of the polygon So: 0.5*(25-15) = 5 diagonals


What is the formula to find the diagonal of trapezoid?

The formula for finding the diagonals of any polygon is: 0.5*(n2-3n) where n = the number of sides. A trapezoid has 4 sides so: 0.5*(16-12) = 2 diagonals


WHAT IS THE ANSWER TOD12N(N-3) GIVES THE NUMBER OF DIAGONALS d FOR A POLYGON WITH N SIDES.. use THIS EQUATION TO FIND THE NUMBER OF DIAGONALS FOR POLYGON THAT HAS 13 SIDES .SOLVE?

65


Where d is the number of diagonals of a polygon with n sides find d if equals 20?

1/2*(n2-3n) = number of diagonals 1/2*(202-60) = 170 diagonals