The Surface area of a triangle = 0.5*base*height The volume of a prism = area of its cross-section*length
ABC is an equilateral triangle with side length equal to 50 cm. BH is perpendicular to AC. MN is parallel to AC. Find the area of triangle BMN if the length of MN is equal to 12 cm.
12
2*area of triangular faces + perimeter of triangle*length of prism (not prisim).
2.08cm. To find the area of any triangle - divide the length of the base by 2, then multiply the result by the height.
V= area of the triangle x length
The measurement of the angle of the triangle...supposing it is a triangle.
The area of any triangle is (1/2 the length of its base) x (its height).
multiply the x-length and the y-length and 2
The area of the triangle in square meters is (1/2 the length of the triangle's base, in meters) times (the length of the triangle's height, in meters).
the area referrers to the length and circumference of the triangle it self. The measurement matters to find the acute angle it self as a angle not a triangle
That's wrong; 18 inch is not a unit of area. In general, since in a square the length and width are the same, you take the square root of the area, to get the length of a side.
to find the surface area of the triangle we just need to multiply the length with breath. area=lengthXbreadth
You cannot unless you have the base
altitude(height)=(Area * 2) /length(Base)
The Surface area of a triangle = 0.5*base*height The volume of a prism = area of its cross-section*length
Formula for area of Triangle: a=0.5(bh) Where b is the base length and h is the height. For example, a triangle of base 10 and height 5 has an area of 25.