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I think the dimensions of the rectangle are 89.5 cm by 90.5 cm but I'm not sure. but that's what i get because if you split the rectangle in to two triangles and you label the hypotenuse 5 cm. and the legs x and (x + 1) you con make the equation: x+(x+1)=180 Then you combine your like terms and you get 2x+1=180. Then you subtract 1 from 180 and get 179. so now you have 2x=179 divide by two and you get x=89.5 and the other side which is 1 cm. longer is 90.5 cm.

I don't know if I'm right but i think i am.

Q: The length of a rectangle is 1 cm longer than its width if the diagonal of the rectangle is 5 cm what are the dimensions of the rectangle in centimeters?

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15 cm for the diagonal.

The dimensions of this rectangle are that its length is equal to 16 centimeters and its width is equal to 9 centimeters. To find these answers, you need to solve for two unknowns L and W in the equations L- W is equal to 7 and 2 x L plus 2 x W is equal to 50, where L is length and W is width.

By Pythagoras, the length of the diagonal = sqrt[(1.8)2 + (1.2)2] = sqrt[3.24 + 1.44] = sqrt[4.68] = 2.16 m

The diagonal is 3.61cm

To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.

Related questions

15 cm for the diagonal.

Using Pythagoras' theorem the length of the diagonal is 20 feet

If they are the dimensions of a rectangle then use Pythagoras' theorem to find the length of the diagonal.

You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com

If you know its dimensions then use Pythagoras' theorem to find the length of its diagonals.

Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters

The diagonal is 7.21 feet.

The dimensions of this rectangle are that its length is equal to 16 centimeters and its width is equal to 9 centimeters. To find these answers, you need to solve for two unknowns L and W in the equations L- W is equal to 7 and 2 x L plus 2 x W is equal to 50, where L is length and W is width.

Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764

To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).

Half a rectangle is a right angled triangle. Pythagoras : Triangle whose hypotenuse is 5 and one side is 1 unit greater than the third must be a 3-4-5 triangle, so the rectangle is 3 cm x 4 cm

The length of the diagonal is about 16.03 feet.