The diagonal is 3.61cm
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
18.9 feet
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.
You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
18.9 feet
If by that you mean knowing only the diagonal and the width, then by the formula a2+b2=c2, where a is the length, b the width and c the diagonal. To find the width b, you need to calculate sqrt(c2-a2). For example, the width of a rectangle with length 3 and diameter 5 is sqrt(52-32)=4
Assuming you're talking about a rectangle: Diagonal squared = length squared + width squared (Pythagoras) so: Length squared = diagonal squared - width squared ie length = sqrt (diagonal squared - width squared)
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
infinitely far
18.9 feet
The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.