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The diagonal is 3.61cm

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Q: The length of a rectangle is 2 cm and the width is 3 cm Find the length of the diagonal?
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What are the steps taken to get the diagonal measurement of a rectangle?

-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.


How do you find the length of a rectangle knowing ONLY the diagonal and the width?

You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.


How do you find diagonal of rectangle when perimeter and width are known?

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]


How do you find the width and length of a rectangle if you only know the diagnol?

If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.


What is the length of a diagonal rectangle with a length of 9 inches and a width of 3 inches?

To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.


How do you find the length of a rectangle knowing ONLY the diagonal and the length?

If by that you mean knowing only the diagonal and the width, then by the formula a2+b2=c2, where a is the length, b the width and c the diagonal. To find the width b, you need to calculate sqrt(c2-a2). For example, the width of a rectangle with length 3 and diameter 5 is sqrt(52-32)=4


How do you find length with width and diagonol numbers?

Assuming you're talking about a rectangle: Diagonal squared = length squared + width squared (Pythagoras) so: Length squared = diagonal squared - width squared ie length = sqrt (diagonal squared - width squared)


How do you find the area of a rectangle with the diagonal of 13 and a width of 5?

if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units


Find the width of a rectangle with a length of 8cm and a diagonal 10cm long?

infinitely far


Find the length of the diagonal of a rectangle that has a length of 16 ft and width of 10 ft?

18.9 feet


Find the length of the diagonal of a rectangle that has a length of 16 ft. and width of 10 ft.?

18.9 feet


How do you find the area of a rectangle given the length and diagonal?

The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.