12
x2/52 + y2/93 = 1
bx2/14 +y2/25 =1
7
x/^2/14^2+y^2/7^2=1
APEXx^2/6^2 + y^2/4^2=1~PurpleLicious~
The length of the major axis of an ellipse is determined by the lengths of its semi-major and semi-minor axes. In this case, if the red line segment represents the semi-major axis (8), the length of the major axis would be twice that, which is 16. The blue line segment, being shorter (4), represents the semi-minor axis. Thus, the major axis of the ellipse is 16 units long.
To determine the length of the blue line segment, we need to know the dimensions of the ellipse, specifically its semi-major and semi-minor axes. The length of the blue line segment typically represents the length of the semi-minor axis if it is perpendicular to the major axis. If the semi-major axis length is provided, the length of the blue line segment can be found using the ellipse's equation or geometric properties. Without specific dimensions, it's not possible to give a numerical answer.
24
10
26
21
24
The answer will depend on what, if anything, the line segments have to do with the ellipse.
The Answer Is 9.5
The length of the major axis of an ellipse is equal to twice the length of the semi-major axis. If the semi-major axis is denoted as "a," then the major axis length is 2a. This axis is the longest diameter of the ellipse, stretching from one end of the ellipse to the other through the center.
8
4 not 9..... ANSWER FOR APEX 10 (: