Supplement angles add up to one hundred eighty degrees, so the supplement of an eighty five degree angle would be a ninety five degree angle.
Complementary angles are angles that add up to 90 degrees. If the smaller angle is x, the larger is 5x, so 6x = 90. X equals 15, and the larger angle measures 75 degrees.
Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
The angles are supplementary ===> A + B = 180 ===> A = 180 - B. Next statement: 3A = 2B - 5 (We don't know or care yet which one is larger, nor do we need to. That will come out on its own.) Substitute the first into the second: 3(180-B) = 2B-5 ===> (540-3B) = (2B-5 ) ===> 540 = 5B-5 ===> 545 = 5B109 = B ===> 71 = A
An angle of thirty-five degrees, and any angle less than 90 degrees is an acute angle.
The angles are: 150+30 = 180 degrees
Supplement angles add up to one hundred eighty degrees, so the supplement of an eighty five degree angle would be a ninety five degree angle.
74
15°
Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.
The supplement of an angle is (180) minus (the angle).Here we have an angle 'A', and we are told that: 2( 180 - A ) = 30 + 5( 180 - A ). We calculate:360 - 2A = 30 + 900 - 5A = 930 - 5A (clear parentheses)3A = 570 (Add 5A - 360 to both sides)A = 190 (Divide both sides by 3)Check:Its supplement is (180 - 190) = -102(-10) (?=?) 30 + 5(-10)-20 (?=?) 30 - 50-20 = -20 Yes !
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Suppose the angle is x degrees. Then its supplement is 180-x. One-third its supplement is (180-x)/3 = 60-x/3 so x/2 = 60-x/3+25 5x/6 = 85 ie x = 102.
The degree measure of five fourths of a right angle is 112.5 degrees
130 Degrees180-24=156So you know that the sum of all the angles is 180, so the sum of the other two angles is 156. You Know that angle p is equal to some number x. And you know the angle n is five times some number x or 5x. You know the sum of the two angles numerically and algebraically.6x=156x=26n=5xn=5(26)n=130
Complementary angles are angles that add up to 90 degrees. If the smaller angle is x, the larger is 5x, so 6x = 90. X equals 15, and the larger angle measures 75 degrees.
Complementary angles add up to 90 degrees. If one angle is five times the measure of the other, you can express their measurements as 5x and x. The original angle is x degrees and its complement is 5x degrees. Set the sum of the two angles equal to 90 and solve for x. 5x + x = 90 6x = 90 x = 15 The angle is 15 degrees. Its complement is 5(15) = 75 degrees. 75 + 15 = 90.