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Suppose the angle is x degrees. Then its complement is x/5 deg So x + x/5 = 90 or 6x = 450 ie x = 75 degrees.
The supplement of an angle x is equal to 180 - x. The measure of an angle that is nine times its supplement can be written as: x = 9(180 - x) You can then solve for the measure of the angle x: x = 1620 - 9x 10x = 1620 x = 162 Therefore, that angle which is nine times its supplement is itself 162 degrees.
15 and 75
Complementary angles add up to 90 degrees and so 4 times 22.5 degrees = 90 degrees or if you mean 4 times 90 degrees then it is a full turn of 360 degrees
The angle is 160 degrees and it's supplement is 20 degrees.
15°
The angle= 36, the supplement= 144, the compliment=54
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explement of the angle or conjugate of an angle
Complementary angles add up to 90 degrees. If one angle is five times the measure of the other, you can express their measurements as 5x and x. The original angle is x degrees and its complement is 5x degrees. Set the sum of the two angles equal to 90 and solve for x. 5x + x = 90 6x = 90 x = 15 The angle is 15 degrees. Its complement is 5(15) = 75 degrees. 75 + 15 = 90.
Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
Suppose the angle is x then its complement is 90-x So 4*(90-x) = x or 360 - 4x = x so that 360 = 5x => x = 72 degrees
Suppose the angle is x degrees. Then its complement is 90 - x deg So 90 - x = 4*x ie 90 = 5x or x = 18 degrees.
Suppose the angle is x degrees. Then its complement is x/5 deg So x + x/5 = 90 or 6x = 450 ie x = 75 degrees.
an angle that is 54 degrees less than 4 times its complement
Let the angle be A, then the supplementary angle is (180 - A) and the complementary angle is (90 - A). But, 180 - A = 10(90 - A) = 900 - 10A 9A = 720 A = 80° The supplementary angle = 100° and the complementary angle = 10°
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