Suppose the rectangle has length L and width W where, as per convention, L >= W.
Now Perimeter = 22 = 2(L+W) so L+W = 11
L is a whole number >=11/2 ie L >= 6
Also, W>0 so L <= 10.
Thus L = 6,7,8,9,10 giving 5 possible areas for the rectangle.
You simply have to measure all the sides of the oblong and add them together. If the opposite sides of it are equal (making it a rectangle), then you just need to measure the two different sides and add them together, then multiplying the result by 2. perimeter = a + b + c +d or perimeter = 2(a+b)
Add together all the sides... i.e. Area(rectangle) = 2(l+w)
the measure for a regular rectangle is 69in. by fudge you and measure it yourself.
84
Assuming the shape of the parcel is a square, the perimeter length will be 1,181 feet. Since "acre" is an area of measure (43,560 sq ft) without set dimentions, the perimeter can be many different numbers.
perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)
Yes.
Perimeter is the sum of the measures of the side lengths. A rectangle with length 15 and width 7 has two sides that measure 15 and two that measure 7. So 7 + 7 + 15 + 15 = 44 is the perimeter.
1.) You can measure the sides of the shapes and add
Measure and add together the 4 sides
You simply have to measure all the sides of the oblong and add them together. If the opposite sides of it are equal (making it a rectangle), then you just need to measure the two different sides and add them together, then multiplying the result by 2. perimeter = a + b + c +d or perimeter = 2(a+b)
Yes. The perimeter is a measure of the combined length of all the sides. If you double the lengths of the sides then naturally this will also necessarilychange the perimeter (it will double the perimeter).
5 meters
That's because you can easily have two different shapes with the SAME perimeter, and DIFFERENT areas, or vice versa. Here is an example:* A 2x2 rectangle has an area of 4, and a perimeter of 8. * A 1x3 rectangle has an area of 3, and a perimeter of 8. * A 0x4 rectangle has an area of 0, and a perimeter of 8. (If you don't like this rectangle, you can make one that is arbitrarily close, i.e., a very small width.) Note that for two SIMILAR figures, any linear measurements are proportional to the scale size, and any area measure is proportional to the square of the scale size - that will make the area proportional to the perimeter, but only for two similar shapes, e.g., two rectangles with the same length-to-width ratio.
The area cannot be 15 feet since that is a measure of length, not area. In any case, information about the area cannot determine the perimeter; it can only put a lower limit on it. The perimeter can be anyhting from 15.49193 ft upwards. Consider the following rectangles, all with area = 15 square feet: a sqrt(15)*sqrt(15) rectangle will have a perimeter of 4*sqrt(15) = 15.49193 ft (approx). 1ft*15ft rectangle will have a perimeter of 32 feet 0.1ft*150ft rectangle: perimeter = 300.2 feet 0.01ft*1500ft rectangle: perimeter = 3000.02 ft 0.001ft*15000ft rectangle: perimeter = 30000.002 ft by now you should see that there is no upper limit to the perimeter.
Add together all the sides... i.e. Area(rectangle) = 2(l+w)
You multiply the length by 2 (because there are two sides of the rectangle that have that measure). You then subtract that number from the perimeter. The number you will be left with is twice the width, so you divide that by two and you get the width of the rectangle.