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The point at which the diagonals of a parallelogram intersect is equidistant from the four vertices?
Wiki User
∙ 11y ago
sometimes
Wiki User
∙ 11y ago
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How many triangles are formed by the diagonals from six vertices of a hexagon?
The three major diagonals in an ordinary hexagon do not intersect at the same point. Therefore, in such a hexagon, the diagonals form 111 triangles.
Prove that if the diagonal of a parallelogram does not bisect the angles through the vertices to which the diagonal is drawn the parallelogram is not a rhombus?
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
Which point in a triangle is equidistant from the vertices's of the triangle?
Not sure about vertices's. The circumcentre is equidistant from a triangle's vertices (no apostrophe).
Does a rhombus have at least have one right angle?
The vertices of a rhombus have no right angles but its diagonals intersect each other at right angles.
What is the Circumcenter Conjecture?
The circumcenter of a triangle is equidistant from the vertices.
Do the point at which the diagonals of a parallelogram intersect is always equidistant from the four vertices?
No because the diagonals of a parallelogram are of different lengths
The point at which the diagonal of a parallelogram intersect is equidistant from the four vertices?
sometimes
The point at which the diagonals of a parallelogram intersect is. equdistant from the four vertices?
The statement is no true.
How many triangles are formed by the diagonals from six vertices of a hexagon?
The three major diagonals in an ordinary hexagon do not intersect at the same point. Therefore, in such a hexagon, the diagonals form 111 triangles.
Prove that if the diagonal of a parallelogram does not bisect the angles through the vertices to which the diagonal is drawn the parallelogram is not a rhombus?
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
What are the lengths of the diagonals and their point of intersection of a quadrilateral with vertices at 1 7 and 7 5 and 6 2 and 0 4?
The given vertices when plotted on the Cartesian plane forms a rectangle with diagonals of square root of 50 in lengths and they both intersect at (3.5, 4.5)
Which point in a triangle is equidistant from the vertices's of the triangle?
Not sure about vertices's. The circumcentre is equidistant from a triangle's vertices (no apostrophe).
Is the centroid equidistant from the vertices's of a triangle?
No. and it is not vertices's! vertices will do.
Does a rhombus have at least have one right angle?
The vertices of a rhombus have no right angles but its diagonals intersect each other at right angles.
What is a segment that two nonconsecutive vertices's of a polygon what are the diagonals for the rhombus?
They are diagonals. In a rhombus, diagonals join opposite vertices.
Is the circumvention is equidistant from the vertices's of a triangle?
Circumvention means to surround or to go around or bypass. It is not a geometric term and has nothing whatsoever to do with a triangle. The circumcentre is equidistant from the vertices (not vertices's!).
Is t he two diagonals connecting opposite corners of a rhomboid must always be equal?
This is false for all rhomboids (a distinct parallelogram such that 4 sides are equal, and has non-right angles), since by congruency, a parallelogram can be flipped on its axis (with 2 closer vertices), producing 2 unequal length diagonals.
